Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
7/2= radius (3.5)
V=πr2^<span>h
V=</span><span>π3.52*12
V= 461.81 </span>
F = 18 ft.
The law of cosines states
c² = a² + b² - 2ab cos C
Using our information, we have
c² = 23² + 16² - 2(23)(16)cos 52
c² = 529 + 256 - 736cos 52
c² = 785 - 736cos 52
c² = 331.8732
Taking the square root of both sides, we have
c = √331.8732 = 18.22 ≈ 18
So u have to rearrange to find x again
You look at the equation and u can see that if u take away 14 from both sides it will leave u with:
X/-3<-2
Now as x is over - 3, the opposite of divide is multiply, so you multiply both sides by - 3.
This leaves you with your answer:
x<6
So the number line which represents this is C.
The length of each side of the larger square is 8 cm.
<u>Step-by-step explanation</u>:
Step 1 ;
- The combined area of two squares = 80 sq.cm
- The side of small square = x
- The side of larger square = 2x
Step 2 :
Area of the square = a^2
Area of small square + area of large square = 80
x^2 + (2x)^2 = 80
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 80/5
x^2 = 16
x = ±4
Step 3 :
Since length cannot be negative, the value of x= 4
∴ The length of the side of small square = 4cm
The length of the side of larger square = 2x = 8cm
