The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
answer C.
Step-by-step explanation:
it has the most logical explanation, frankly I'm not the best with circles, but I'm decently sure I'm right
Triangles ABC and ADE are similar triangles. That means the sides are all scaled by the same factor.
To go from side BC to side DE, you multiply by 1.25. That means 1.25 is your scale factor. Now apply that factor to the bottom side to get your answer.
Side AB is 6. That means side AD is 6 x 1.25 = 7.5. That means x = 7.5 - 6 = 1.5
Lines y=-x+2 and y=3x+1 intersect the y=axis. If you plot them out on a graph using the equation y=mx+b, then they are parallel and are set on the y-axis.
The answer is #2 you’re welcome
