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2 years ago

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A movie theater has a seating capacity of 379. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.

There are half as many adults as there are children. If the total ticket sales was $ 2746, How many children, students, and adults attended?

1 answer:

ELEN [110]2 years ago

8 0

Answer:

ifiediuyuhrhhxydjfhf

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Xy has 10 pets: 4 dogs, 3 cats, 2 alpacas and 1 bunny. If he wants to arrange them in a row and make sure the pets are always gr

Anastaziya [24]

The number of ways pets can be arranged in group according to the species is in a row 288 ways.

Pets can be grouped by permutation concept as follows.

Total number of pets = 10

Number of dogs = 4

Number of cats = 3

Number of alpacas = 2

Number of bunny = 1

The number of ways pets can be arranged in group according to the species in a row as,

⇒ (4!)(3!)(2!)(1!)

⇒ (24)(6)(2)(1)

⇒ 288

Hence we can conclude that the number of ways pets can be arranged in group according to the species in a row is 288 ways.

Learn more about permutation here

brainly.com/question/22444718

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8 0

2 years ago

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic

Free_Kalibri [48]

The equation for the situation is $y=200(\frac{2}{3})^{x}$

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is $y=a(b)^{x}$ , where

a is the initial value
b is the growth/decay factor
If b > 1, then it is a growth factor
If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is $\frac{2}{3}$

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is $y=a(b)^{x}$ , where y represent the

population in x years

∵ a = 200

∵ b = $\frac{2}{3}$

∴ $y=200(\frac{2}{3})^{x}$

The equation for the situation is $y=200(\frac{2}{3})^{x}$

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ $5=200(\frac{2}{3})^{x}$

- Divide both sides by 200

∴ $0.025=(\frac{2}{3})^{x}$

- Insert ㏒ for both sides

∴ $log(0.025)=log(\frac{2}{3})^{x}$

∴ $log(0.025)=xlog(\frac{2}{3})$

- Divide both sides by $log(\frac{2}{3})$

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation in brainly.com/question/10666510

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8 0

3 years ago

5x + 4x2 - 9x + 8x2

natima [27]

Answer:

12x^2-4x

Step-by-step explanation:

5x + 4x^2 - 9x + 8x^2

Combine like terms

4x^2+8x^2+5x-9x

12x^2-4x

4 0

3 years ago

Read 2 more answers

Explain how to subtract 247 from 538

Vladimir79 [104]

8-7=1 3-4=1 5-2=3 So it is 311.

4 0

3 years ago

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

So

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

3 0

3 years ago