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3 years ago

If f(x) = 2x^2+1 and g(x) =x^2-7 find (f+g)(x)

Mathematics

2 answers:

alekssr [168]3 years ago

7 0

F(x) + g(x) = [2x^2 + 1] + [x^2 – 7]

≈ 3x^2 – 6

Hence (f + g)(x) = 3x^2 – 6

sp2606 [1]3 years ago

5 0

Answer:f=−

 +1−2g−x

Step-by-step explanation:

1 Subtract {x}^{2}x

from both sides.

2{x}^{2}+1-g-x-{x}^{2}=-7f+g2x

+1−g−x−x

=−7f+g

2 Simplify 2{x}^{2}+1-g-x-{x}^{2}2x

+1−g−x−x

to {x}^{2}+1-g-xx

+1−g−x.

{x}^{2}+1-g-x=-7f+gx

+1−g−x=−7f+g

3 Subtract gg from both sides.

{x}^{2}+1-g-x-g=-7fx

+1−g−x−g=−7f

4 Simplify {x}^{2}+1-g-x-gx

+1−g−x−g to {x}^{2}+1-2g-xx

+1−2g−x.

{x}^{2}+1-2g-x=-7fx

+1−2g−x=−7f

5 Divide both sides by -7−7.

-\frac{{x}^{2}+1-2g-x}{7}=f−

+1−2g−x

6 Switch sides.

f=-\frac{{x}^{2}+1-2g-x}{7}f=−

+1−2g−x

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