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lyudmila [28]
3 years ago
11

Someone help with this please

Mathematics
1 answer:
Flauer [41]3 years ago
4 0
I think it’s A but i’m not for sure but i think so but sorry if i’m wrong
You might be interested in
Simone measures the width of one of cardboard strip as 1/2 yard. A second cardboard strip measures 5/6 yard in width. Estimate t
Zepler [3.9K]

Answer:

The correct option is C. About 1 on the side with the 1 on top and 4 on the bottom yard.

Step-by-step explanation:

Consider the provided information.

Simone measures the width of one of cardboard strip as 1/2 yard.

A second cardboard strip measures 5/6 yard in width.

We need to find the combined width.

The combined width of the cardboard strip:

\frac{1}{2} + \frac{5}{6}=\frac{8}{6}=1\frac{1}{3}

1\frac{1}{3} is closer to1\frac{1}{4} as compare to 1\frac{1}{2}

Hence, the correct option is C. About 1 on the side with the 1 on top and 4 on the bottom yard.

3 0
3 years ago
Solve for :<br>(x+3)/2=6​
Marianna [84]

Answer:

x=9

Step-by-step explanation:

(x+3)/2=6​

Multiply each side by 2

2*(x+3)/2=6*2

x+3 = 12

Subtract 3 from each side

x+3-3 = 12-3

x = 9​

5 0
3 years ago
I need help please. Must be correct. 10 points. Thanks
Anna11 [10]

We have the supplementary angles.

The sum of the measures of the two Supplementary Angles is 180°.

Therefore we have the equation:

13x - 2 + 39 = 180

13x + 37 = 180     <em>subtract 37 from both sides</em>

13x = 143      <em>divide both sides by 13</em>

<em>x = 11</em>

<h3>Answer: 11</h3>
5 0
3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
4 years ago
A specific laptop loses half of its value every six months. If the original cost was $1000 and the value of the laptop is now $6
mafiozo [28]

Answer:

Sigh no body wants to answer this one, so I'll just take my points back

4 0
3 years ago
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