Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
False
foci of an ellipse cannot be outside the ellipse
750 is ?% of 625
<em>Y = ?% * X</em>
Solving our equation for ?
?% = Y/X
?% = 750/625
? = 1.2
Convert decimal to percent:
<span>?% = 1.2 * 100 = 120%
</span>
Class 8 is 120% of Class 7.
If you want the percent of Class 8 to Class 7, it is:
625 is ?% of 750
<em> = ?% * X</em>
Solving the equation for ?
?% = Y/X
?% = 625/750
? = 0.8333
Convert decimal to percent:
<span>?% = 0.8333 * 100 = 83.33%
</span>Class 7 is 83.33% of Class 8.
