I need help 25 points

Sever21 [200]

The answer is C) all real numbers greater than or equal to one.

Hope this helps!

4 0

2 years ago

PLZ HELP ASAP The numbers of motor vehicle fatalities in the United States for the years 2010 and 2011 are listed in the table b

Nonamiya [84]

To find which measure of variability is greater and which average number of monthly fatalities is higher, you will need to calculate the mean and the mean absolute deviation for both years

The mean will tell us which is generally higher, and the mean absolute deviation will tell us which has a greater variability.

The correct answer is D.

Please see the attached picture for the work.

5 0

2 years ago

Alice's grandfather is showing Alice his apple

Amanda [17]

There are 156 rows of trees altogether.

<u>Step-by-step explanation:</u>

Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.

Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious.

Number of rows of Royal Gala=18

$corresponding\ number\ of\ Red\ delicious\ = 11/3 \times 18=11\times 6=66$

For 11 rows of red delicious,they plant 7 rows of yellow delicious.

Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.

For 66 rows of red delicious there would be

$7/11\times66=7\times 6=42 rows\ of\ yellow\ delicious$

For 11 rows of red delicious,they plant 5 rows of Braeburn

for 1 row of red delicious,they would plant 5/11 rows of Braeburn.

For 11 rows of red delicious,they would plant

$5/11\times 66=5\times 6=30\ rows\ of\ braeburn$

Total rows of trees=66+42+30+18=156

8 0

3 years ago

Use quadratic regression to find

vovangra [49]

Answer:

y = 6x² -13x -5

Step-by-step explanation:

(1,-12) (2,-7) (5,80)

y = ax² + bx + c

-12 = a*1² + b*1 + c = a+b+c (1)

-7 = 4a + 2b + c (2)

80 = 25a + 5b + c (3)

(2)-(1): 3a + b = 5 (4)

(3)-(2): 21a + 3b = 87 (5)

(4)*3: 9a + 3b = 15 (6)

(5)-(6): 12a = 72 a = 6

(4) b = -13

(2) c = -5

4 0

2 years ago

f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2

iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4, $\infty$ )

g(x)= $2x^2+8x+6=2(x^2+4x+3)$

$g(x)=0$

$2(x^2+4x+3)=0$

$x^2+4x+3=0$

$x^2+3x+x+3=0$

$x(x+3)+1(x+3)=0$

$(x+1)(x+3)=0$

$x+1=0\implies x=-1$

$x+3=0\implies x=-3$

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

$g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2$

$g(x)=2(x^2+4x)+6$

$g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6$

$g(x)=2(x+2)^2-2$

By comparing with the equation of parabola

$y=a(x-h)^2+k$

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2, $\infty$ )

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0

2 years ago