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3 years ago

(3 points)

Mathematics

1 answer:

Snezhnost [94]3 years ago

6 0

Answer:

The exponential Function is $20+12h=200$ .

Farmer will have 200 sheep after 15 years.

Step-by-step explanation:

Given:

Number of sheep bought = 20

Annual Rate of increase in sheep = 60%

We need to find that after how many years the farmer will have 200 sheep.

Let the number of years be 'h'

First we will find the Number of sheep increase in 1 year.

Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.

framing in equation form we get;

Number of sheep increase in 1 year = $\frac{60}{100}\times20 = 12$

Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years is equal to 200.

Framing in equation form we get;

$20+12h=200$

The exponential Function is $20+12h=200$ .

Subtracting both side by 20 using subtraction property we get;

$20+12h-20=200-20\\\\12h=180$

Now Dividing both side by 12 using Division property we get;

$\frac{12h}{12} = \frac{180}{12}\\\\h =15$

Hence Farmer will have 200 sheep after 15 years.

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kirza4 [7]

Answer:

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3 years ago

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erica [24]

(36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8"
This is the equation that you would get for the average. Now we just solve for z.
Following PEMDAS you have to mulitply the equation by 4 to get rid of the divide by 4 part.
4( (36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8)
Which does this
36 3/4" + 36 3/8" + 371/2" +z = 146 1/2"
Now you have to add and subtract to get "z" by itself.
36 3/4" + 36 3/8" + 371/2" = 110 5/8"
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z= 35 7/8", so the answer is b

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3 years ago

. Kelton made punch for a school dance. He used 2 gallons of apple juice and 3 bottles of ginger ale to make enough to fill two

Sedbober [7]

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Step-by-step explanation:

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2 years ago

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Westkost [7]

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3 years ago

A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi

Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

Let X = number of names recalled

SO, X ~ N( $\mu = 19.41,\sigma^{2} = 3.17^{2}$ )

The z-score probability distribution is given by ;

Z = $\frac{X-\mu}{\sigma} } }$ ~ N(0,1)

where, $\mu$ = mean number of names recalled = 19.41

$\sigma$ = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

P(X > 15) = P( $\frac{X-\mu}{{\sigma} } }$ > $\frac{15-19.41}{3.17} }$ ) = P(Z > -1.39)

= P(Z < 1.39) = 0.9177 {using z table}

Therefore, proportion of the students recalled more than 15 names is 91.77%.

4 0

3 years ago