3 years ago

The sum of two right angles always, sometimes, never results in a straight angle. Justify answer

Mathematics

1 answer:

alekssr [168]3 years ago

3 0

Sometimes
I hope that helps u

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In 20112, it rained 1.651 x 103 centimeters in New Orleans. In 2012 it rained another 8.2 x 102 centimeters. How many centimeter

elixir [45]

Answer:

1,006.453 cm

Step-by-step explanation:

1.651 × 103 = 170.053

8.2 × 102 = 836.400

170.053 + 836.4 = 1006.453 cm

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3 years ago

Find x. to 150 X = Alternate interior angles

cestrela7 [59]

Answer:

x = 115°

Step-by-step explanation:

These angles are actually alternate exterior angles.

Alternate exterior angles are congruent.

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2 years ago

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Enter your answer as a decimal. Round ONLY your final answer to the nearest tenth.

Anastaziya [24]

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PQ^2=81+196-236

PQ^2=41

PQ~6,4

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3 years ago

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Give the equation of the circle centered at the origin and passing through the point (0, -6).

pishuonlain [190]

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Step-by-step explanation:

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8 0

3 years ago

Help me guys thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

Step 1: Multiply

$(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

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3 years ago

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