<h2>
Option B is the correct answer.</h2>
Step-by-step explanation:
We need to find average value of 
in [2,4]
Area of in [2,4] is given by
![\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times \left [ e^{2x}\right ]^4_2\\\\\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times(e^8-e^4)=1463.18](https://tex.z-dn.net/?f=%5Cint_%7B2%7D%5E%7B4%7De%5E%7B2x%7Ddx%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5Cleft%20%5B%20e%5E%7B2x%7D%5Cright%20%5D%5E4_2%5C%5C%5C%5C%5Cint_%7B2%7D%5E%7B4%7De%5E%7B2x%7Ddx%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%28e%5E8-e%5E4%29%3D1463.18)
Area of in [2,4] = 1463.18
Difference = 4 - 2 = 2
Average value = Area of in [2,4] ÷ Difference
Average value = 1463.18 ÷ 2
Average value = 731.59
Option B is the correct answer.
is the equivalent to "five to the third power"
76.25 is the answer because 1525 divided by 20 equals 76.25
Answer:
x ∈ [-2, 7]
Step-by-step explanation:
The given equation ...
x^2 -5x -4 ≤ 10
can be rewritten as ...
x^2 -5x -14 ≤ 0
and factored as ...
(x +2)(x -7) ≤ 0
Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.
x ∈ [-2, 7]
