F=ar^t if the half-life is 96 years...
.5=r^96
ln(.5)=96lnr
ln(.5)/96=lnr
r=e^((ln.5)/96)
f=800e^(336(ln.5)/96)
f=70.71
So about 71mg will remain after 336 years.
Answer:
y = 4/3x + 1
Step-by-step explanation:
slope = rise over run
slope = 4 rise 3 run
slope = 4/3
Answer:
7/10
Step-by-step explanation:
2/5 multiply the denominator by 2 which will make it 10. Then multiply the numerator by 2 which will make it 4. So it will be 4/10. Then add 4/10 to 3/0 which makes 7/10.
