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Anvisha [2.4K]
3 years ago
11

EASY BRAINLIEST PLEASE HELP!!

Mathematics
2 answers:
NARA [144]3 years ago
6 0

Answer:

Solution given:

ABCD is a parallegram.

In ∆ADE and ∆BCE

AD=BC[corresponding side of parallelogram are equal]

<AED=<BEC[ vertically opposite angle]

<ADE=<EBC[alternate angle]

so

∆ADE are congruent to ∆BCE by S.A.A. axiom

we have

DE=BE[corresponding side of congruent triangle are equal]

Similarly

AE=CE

we have

AC=BD

AE+CE=BE+DE

2AE=2BE

AE=BE

so.we can rightly say that AC and BD bisect each other.

Anarel [89]3 years ago
5 0

Answer:

The parallelogram ABCD is what makes the parallelogram.

The proof given was AC and BD bisect each other.

<u><em>Bisect</em></u> means to divide into 2 parts. AC and BD both divide into 2 parts with each other.

But the lines need to be in 2 equal parts.

So if we were to divide it in that case, it would be able to bisect.

This is given proof that parallelogram ABCD is a parallelogram.

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