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Anvisha [2.4K]
3 years ago
11

EASY BRAINLIEST PLEASE HELP!!

Mathematics
2 answers:
NARA [144]3 years ago
6 0

Answer:

Solution given:

ABCD is a parallegram.

In ∆ADE and ∆BCE

AD=BC[corresponding side of parallelogram are equal]

<AED=<BEC[ vertically opposite angle]

<ADE=<EBC[alternate angle]

so

∆ADE are congruent to ∆BCE by S.A.A. axiom

we have

DE=BE[corresponding side of congruent triangle are equal]

Similarly

AE=CE

we have

AC=BD

AE+CE=BE+DE

2AE=2BE

AE=BE

so.we can rightly say that AC and BD bisect each other.

Anarel [89]3 years ago
5 0

Answer:

The parallelogram ABCD is what makes the parallelogram.

The proof given was AC and BD bisect each other.

<u><em>Bisect</em></u> means to divide into 2 parts. AC and BD both divide into 2 parts with each other.

But the lines need to be in 2 equal parts.

So if we were to divide it in that case, it would be able to bisect.

This is given proof that parallelogram ABCD is a parallelogram.

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Tion 15/30
vitfil [10]

The percentage of students that passed the exam is 25.2%

<u />

<u>The given parameters;</u>

  • number of the males, = 85
  • number of the females, = 30
  • percentage of the female that passed = 40%
  • percentage of the male that passed, = 20%

<u>To find:</u>

  • the percentage of students that passed the exam

The number of the male students that pass the exam;

= 0.2 \times 85 \\\\= 17

The number of the female students that pass the exam;

= 0.4 \times 30 \\\\= 12

The total number of students in the school;

= 85 + 30

= 115

The total number of the students that passed the exam;

= 17 + 12

= 29

The percentage of students that passed the exam;

= \frac{total \ number \ that \ passed }{total \ number \ of \ the \ students} \times 100\% \\\\= \frac{29}{115} \times 100\%\\\\= 25.2 \%

Thus, the percentage of students that passed the exam is 25.2%

Learn more here: brainly.com/question/1163846

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