All categories

3 years ago

EASY BRAINLIEST PLEASE HELP!!

Mathematics

2 answers:

NARA [144]3 years ago

6 0

Answer:

Solution given:

ABCD is a parallegram.

In ∆ADE and ∆BCE

AD=BC[corresponding side of parallelogram are equal]

<AED=<BEC[ vertically opposite angle]

<ADE=<EBC[alternate angle]

∆ADE are congruent to ∆BCE by S.A.A. axiom

we have

DE=BE[corresponding side of congruent triangle are equal]

Similarly

AE=CE

we have

AC=BD

AE+CE=BE+DE

2AE=2BE

AE=BE

so.we can rightly say that AC and BD bisect each other.

Anarel [89]3 years ago

5 0

Answer:

The parallelogram ABCD is what makes the parallelogram.

The proof given was AC and BD bisect each other.

Bisect means to divide into 2 parts. AC and BD both divide into 2 parts with each other.

But the lines need to be in 2 equal parts.

So if we were to divide it in that case, it would be able to bisect.

This is given proof that parallelogram ABCD is a parallelogram.

You might be interested in

Convert 10.3 cm into m

IRISSAK [1]

Answer:

10.3cm=0.103

Step-by-step explanation:

Hope this helped :)

-El

7 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line that satisfies the following condition.

skelet666 [1.2K]

Answer:

The equation of the line we want to write is 4y = -x + 22

Step-by-step explanation:

Here, we want to write the equation of a line

The standard equation of a straight line is given as:

y = mx + c

where m is the slope and c represents the y-intercept

Now, let’s look at the line y = 4x + 16

The slope of this line is 4

Now, the equation of the line we want to write is perpendicular to this line

When two lines are perpendicular, the product of their slopes = -1

Hence;

m * 4 = -1

m = -1/4

So the slope of the line we want to write is -1/4

Now, using the point-slope form for the new equation;

y-y1/x-x1 = m

From the point given (x1,y1) = (10,3)

Thus;

y-3/x-10 = -1/4

4(y-3) = -1(x - 10)

4y - 12 = -x + 10

4y = - x + 10 + 12

4y = -x + 22

4 0

2 years ago

The point (16, 12) lies on the terminal side of an angle. find cos, tan, and sin

frez [133]

The terminal side means that it's 16 to the right and 12 up. Which means that the triangle made from this has the sides of 16 and 12 and the hypotenuse is 20 units long. Theta, in this case, would have 16 as it's adjacent and 12 as it's opposite.
Therefore, using the Pythagorean identities:
 $sin(\theta) = \frac{12}{20} = \boxed{\frac{3}{5}} \\\ cos(\theta) = \frac{16}{20} = \boxed{\frac{4}{5}} \\\ tan(\theta) = \frac{12}{16} = \boxed{\frac{3}{4}}$

8 0

3 years ago

What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1? PLs HELP!!

Delicious77 [7]

ANSWER
$f(x)= \frac{1}{4} {(x - 1)}^{2}$

EXPLANATION

Since the directrix is
$y = - 1$

the axis of symmetry of the parabola is parallel to the y-axis.

Again, the focus being,

$(1,1)$

also means that the parabola will open upwards.

The equation of parabola with such properties is given by,

${(x - h)}^{2} = 4p(y - k)$
where
$(h,k)$

is the vertex of the parabola.

The directrix and the axis of symmetry of the parabola will intersect at
$(1, - 1)$

The vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix.

This implies that,
$h = \frac{1 + 1}{2} = 1$

and
$k = \frac{ - 1 + 1}{2} = 0$

The equation of the parabola now becomes,

$(x - 1) ^{2} = 4p(y - 0)$

$|p| = 1$

Thus, the distance between the vertex and the directrix.

This means that,

$p = - 1 \: or \: 1$

Since the parabola opens up, we choose
$p = 1$
Our equation now becomes,

${(x - 1)}^{2} = 4(1)(y - 0)$

This simplifies to
${(x - 1)}^{2} = 4y$

or

$y = \frac{1}{4} {(x - 1)}^{2}$

This is the same as,

$f(x)= \frac{1}{4} {(x - 1)}^{2}$

The correct answer is D .

4 0

3 years ago

If 12 +22+ 32 +

kakasveta [241]

Answer:

Step-by-step explanation:

the 2nd equation is double the first one and the first one is 1

8 0

1 year ago