EASY BRAINLIEST PLEASE HELP!!
2 answers:
Answer:
Solution given:
ABCD is a parallegram.
In ∆ADE and ∆BCE
AD=BC[corresponding side of parallelogram are equal]
<AED=<BEC[ vertically opposite angle]
<ADE=<EBC[alternate angle]
so
∆ADE are congruent to ∆BCE by S.A.A. axiom
we have
DE=BE[corresponding side of congruent triangle are equal]
Similarly
AE=CE
we have
AC=BD
AE+CE=BE+DE
2AE=2BE
AE=BE
so.we can rightly say that AC and BD bisect each other.
Answer:
The parallelogram ABCD is what makes the parallelogram.
The proof given was AC and BD bisect each other.
<u><em>Bisect</em></u> means to divide into 2 parts. AC and BD both divide into 2 parts with each other.
But the lines need to be in 2 equal parts.
So if we were to divide it in that case, it would be able to bisect.
This is given proof that parallelogram ABCD is a parallelogram.
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A = LW
A = 120
W = L - 2
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<em>I hope this helps you</em>
<em>:)</em>