Answer:
Range = highest value - lowest value
Explanation:
This is the required formula to find range from a distribution table.
Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
Step-by-step explanation:
Given
To find
Solution
- f(19) = 3/(19 + 2) - √(19 - 3) = 3/21 - √16 = 1/7 - 4 = - 27/7
Answer:
The number would be 22.
Step-by-step explanation:
In order to solve for the number, we need to make both statements into numerical statements.
Fifteen more than four times a number = 15 + 4x
difference between 191 and four times the number = 191 - 4x
Now we set them equal to each other.
15 + 4x = 191 - 4x -----> Add 4x to each side
15 + 8x = 191 ------> Subtract 15 from both sides
8x = 176 -------> Divide by 8
x = 22
