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UNO [17]
3 years ago
6

THIS IS MY 3RD TIME POSTING THIS ANSWER PLSSSSSSSS 50 POINTSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

Mathematics
2 answers:
Arturiano [62]3 years ago
7 0

Answer:

m\angle AED=90\degree

m\angle DAE=53\degree

m\angle BCE= 53\degree

Step-by-step explanation:

ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.

Diagonals of a rhombus bisects at right angles.

\therefore m\angle AED=90\degree

In\: \triangle AED

m\angle DAE=90\degree-m\angle EDA

m\angle DAE=90\degree-37\degree

m\angle DAE=53\degree

\because m\angle BCE= m\angle DAE

(Alternate angles)

\therefore m\angle BCE= 53\degree

taurus [48]3 years ago
5 0

Answer:

thxxx

Step-by-step explanation:

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