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lorasvet [3.4K]
3 years ago
15

(PLEASE HELP/LAST QUESTION)

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:

Parallel: y=6x-19

Perpendicular: y=-1/6x-0.5

Step-by-step explanation:

To be parallel to a line, the slope must be the same as the line. Then, you plug 3,-1 into y=6x, and add or subtract to balance the equation. You do the same to find the perpendicular line, but the slope must be the negative reciprocal of the line it is perpendicular to.

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Step-by-step explanation:

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3 years ago
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Suppose the parent population has an exponential distribution with a mean of 15 and standard deviation of 12. Use the Central Li
bazaltina [42]

Answer:

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population, we have that:

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Approximately normal

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

4 0
3 years ago
The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h
BabaBlast [244]

Answer:

The maximum height of the projectile is 90 ft

Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

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y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

K

in this case is 90 and thus, that is the maximum height of the projectile

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