(PLEASE HELP/LAST QUESTION)

Mathematics

1 answer:

Mashcka [7]3 years ago

8 0

Answer:

Parallel: y=6x-19

Perpendicular: y=-1/6x-0.5

Step-by-step explanation:

To be parallel to a line, the slope must be the same as the line. Then, you plug 3,-1 into y=6x, and add or subtract to balance the equation. You do the same to find the perpendicular line, but the slope must be the negative reciprocal of the line it is perpendicular to.

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164,215 rounded to the nearest ten thousand

Dimas [21]

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3 years ago

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Plz help {graphing substitution} best answer = brainliest

Shkiper50 [21]

$2x - 2y = 14 \\ x = 2 + y \\ \\ 2(2 + y) - 2y = 14 \\ 4 + 2y - 2y = 14 \\ 4 = 14$
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3 years ago

Sin theata=3/5, then cos theata= ?

Elena-2011 [213]

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a
\qquad
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{5^2-3^2}=a\implies \pm\sqrt{25-9}=a\implies \pm 4=a
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 4}}{\stackrel{hypotenuse}{5}}~\hfill$