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3 years ago

32 divided by 11 is it two or 10 Please help me

Mathematics

1 answer:

mars1129 [50]3 years ago

5 0

Answer:

2 with a remainder of 10

Step-by-step explanation:

11 goes into 32 2 times which is 22. Then there is 10 leftover as a remainder.

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Asking easy questions so people can get points (answer must be right)<br><br> what is 0.45 x 10

nexus9112 [7]

Answer:

Thank youuu It's 4.5

Step-by-step explanation:

3 0

3 years ago

The "int()" operator in your calculator is the "greatest integer function." It returns the greatest integer less than or equal t

Leona [35]

The function that correctly returns grades from 60 percent to a 100 percent is f(x) = [[(x - 50)/10]]

<h3>How to determine this function</h3>

The question tells us that the students do not fail and they do not get a 100 percent score either.

Hence there is no need for worry if the grade is at 5.0 or less than 1.

For example we have

x = 82.976

f(82.976) =[[(82.976-50)/10]

This would then be 3.29

This is then = 3.0

This function is not an odd function and it is not an even function. This is because the domain does not have negative values.

Read more on the domain of a function here:

brainly.com/question/1369616

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5 0

2 years ago

HELP I ONLY HAVE LIKE 5 MINUTES LEFT I WILL MARK YOU AS BRAINLIEST!!

elena-14-01-66 [18.8K]

Answer:

-3 x 3 is 9 and -3 x -432 is 1296 and 3 x 432 is 1296 if that helps

Step-by-step explanation:

5 0

3 years ago

Which expression is equivalent to RootIndex 3 StartRoot StartFraction 75 a Superscript 7 Baseline b Superscript 4 Baseline Over

slega [8]

Answer:

B. $\frac{b}{2a^{2}c^3}\sqrt[3]{15b}$

Step-by-step explanation:

Given:

The expression to simplify is given as:

$\sqrt[3]{\frac{75a^7b^4}{40a^{13}c^9}}$

Use the exponent property $\frac{a^m}{a^n}=a^{m-n}$

$\frac{a^7}{a^{13}}=a^{7-13}=a^{-6}$

Use the exponent property $(a^m)^n=a^{m\times n}$

$a^{-6}=a^{-2\times 3}=(a^{-2})^3$

$b^4=b\times b^3\\c^{9}=(c^3)^3$

Reducing $\frac{75}{40}$ to simplest form, we get:

$\frac{5\times 5\times 3}{2^3\times 5}=\frac{15}{2^3}$

Therefore, expression becomes:

$\sqrt[3]{\frac{15(a^{-2})^3\times b\times b^3}{2^3(c^3)^3}}$

Use the cubic root property:

$\sqrt[3]{x^3} =x$ . Thus, the expression becomes:

$\frac{a^{-2}b}{2c^3}\sqrt[3]{15b}$

Using the exponent property $a^{-m}=\frac{1}{a^m}$

$a^{-2}=\frac{1}{a^2}$

So, the final expression is:

$\frac{b}{2a^{2}c^3}\sqrt[3]{15b}$

Therefore, the correct option is option B.

7 0

4 years ago

CAN SOMEONE PLEASE HELP ME OUT PLEASE I WOULD APPRECIATE IT VERY MUCH

tatyana61 [14]

Answer:Decreasing

Step-by-step explanation:

Focus only on the 8-10 interval for x. Note that for x=8 , y=1, for x=9, y=0 and for x=10, y=-1. Y is obviously decreasing for $8$ .

6 0

3 years ago