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2 years ago

59 and/or 60. Determine if the triangles are similar. If they are similar, find the scale factor from ABC to JKL.

Mathematics

1 answer:

navik [9.2K]2 years ago

8 0

9514 1404 393

Answer:

59) not similar

60)

Step-by-step explanation:

59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.

7:8:12 ≠ 6:7:11

60) The side length ratios both reduce to 8:7:10, so the triangles are similar.

∆ABC ~ ∆JKL

The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)

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zheka24 [161]

Answer:

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Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

$\sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}$

s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$

Where:

$\bar x$ = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

$\bar x$ = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$ = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

$C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }$

$\sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{0.872}}$

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The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

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3 years ago

20. A cement mixer held 6 3/4 tons of cement. Ms. Folley used 2/3 of the cement for her driveway. How many tons of cement remain

NNADVOKAT [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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$f(25)=25 and f(0) = 0\\f'(c) = 1$

For the given function

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