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2 years ago

59 and/or 60. Determine if the triangles are similar. If they are similar, find the scale factor from ABC to JKL.

Mathematics

1 answer:

navik [9.2K]2 years ago

8 0

9514 1404 393

Answer:

59) not similar

60)

Step-by-step explanation:

59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.

7:8:12 ≠ 6:7:11

60) The side length ratios both reduce to 8:7:10, so the triangles are similar.

∆ABC ~ ∆JKL

The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)

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There are 60 girls and 90 boys in the sixth grade at a middle school. What percent of the sixth graders at this middle school ar

KonstantinChe [14]

Answer:

60%

Step-by-step explanation:

First, find the total number of sixth graders

To do this, add the number of girls and boys together

girls+boys

There are 60 girls and 90 boys

60+90

150

Now, find the percent of sixth graders that are boys

To do this, divide the number of boys by the total number of sixth graders

boys/total sixth graders (part/whole)

There are 90 boys, and 150 total sixth graders

90/150

0.6

Convert to a percent. Multiply by 100 or move the decimal place two spots to the right

0.6*100=60

0.6-->6.0-->60.

So, 60% are boys

3 0

2 years ago

a shopkeeper purchased a TV at ₹15,000 and gives a discount of 20% on its marked prize and still got a profit of 8% . find the m

Setler79 [48]

$\huge\sf\underline{Answer}$

$\sf\longrightarrow selling \: prize \: = \frac{100 + profit\%}{100} \times cp$

$\sf\longrightarrow \frac{108}{100} \times 15000 = 16200$

Let the marked prize of the TV be x .

$\sf\longrightarrow discount = 20\% \: of \: x \: = \frac{20}{100}x = \frac{x}{5}$

We have SP = MP - Discount

$\sf\longrightarrow 16200 \: = \: x - \frac{x}{5}$

$\sf\longrightarrow 16200 \: = \frac{4x}{5}$

$\sf\longrightarrow x \: = \: 20250$

Hence , The marked prize of the TV is ₹20,250 .

Hope it helps ~

7 0

1 year ago

Solve the problem. Round the point estimate to the nearest thousandth. Find the point estimate of the proportion of people who w

Blababa [14]

Answer:

b. 0.055

Step-by-step explanation:

The point estimate of the proportion of people who wear hearing aids is

The number of people in the sample who wear hearing aids divided by the total number of people in the sample.

In this problem, we have that:

Sample of 855.

47 people in the sample had hearing aids.

47/855 = 0.0549

Rounding up

0.055

So the correct answer is:

b. 0.055

4 0

2 years ago

Kris has finished 7/8 of 40 questions. how many were done

VLD [36.1K]

7/8=0.875

0.875 x 40= 35

Therefore, Kris has finished 35 questions.

Hope this helps.

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2 years ago

Make x the subject! urgent help

Serhud [2]

Answer:

$x = \frac{n}{b - {t}^{2} }$

Step-by-step explanation:

I supposed that is a "n".

Steps as below:

${t}^{2} = b - \frac{n}{x} \\ b - \frac{n}{x} = {t}^{2} \\ - \frac{n}{x} = {t}^{2} - b \\ \frac{n}{x} = - ( {t}^{2} - b) \\ \frac{n}{x} = b - {t}^{2} \\ n = x(b - {t}^{2} ) \\ x(b - {t}^{2} ) = n \\ x = \frac{n}{b - {t}^{2} }$

4 0

1 year ago

Read 2 more answers