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marshall27 [118]
3 years ago
15

Ashley drove 693 miles in 11 hours

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
6 0

Answer:

and 63 miles in 1 hour......

mr_godi [17]3 years ago
3 0

Answer:

Is there a question or not??

Step-by-step explanation:

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Graph the image of the given triangle, reflected across the y-axis. Select the Polygon tool. Then, click the points of the trian
yawa3891 [41]

1) We are given a hexagon there.

Sum of all angles of a hexagon is 720.

Therefore, sum of all angles inside pentagon =720.

We can step an equation as

x+100+102+108+121 = 720.

Adding 100+102+108+121, we get 431.

Therefore,

x+431 = 720.

Subtracting 431 from both sides, we get

x+431-431 = 720-431

x=289.

Therefore, measure of unknown angle x= 289 degrees.


2) Coordinates of the vertices of the given triangle

(-2,-9)

(7,-4)

(9,-7).

We need to graph the reflected triangle across the y-axis.

For reflected triangle across the y-axis we can apply rule

(x,y) --> (-x,y)

By applying above rule, we get the coordinates of reflected triangle as

(-2,-9)  --> (2,-9)

(7,-4)   --> (-7,-4)

(9,-7)   --> (-9,-7).

Now, we can plot those coordinates on the graph and join the coordinates to form a triangle.

4 0
4 years ago
Read 2 more answers
Can someone help me please thank you
serious [3.7K]

Answer:

15 <u><</u> x <u><</u> 18? I don't know. Is that what you're looking for?

Step-by-step explanation:

3 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary)
Andrews [41]

Answer:

The answer is

<h2>2.8 units </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-3,3) and (-1,5)

The distance is

d =  \sqrt{( { - 3 + 1})^{2} +  ({3 - 5})^{2}  }    \\  =  \sqrt{ ({ - 2})^{2} + ( { - 2})^{2}  }  \\  =  \sqrt{4 + 4}  \\  =  \sqrt{8}  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 2 \sqrt{2}  \:  \:  \:  \:  \:  \:  \\  = 2.82842

We have the final answer as

<h3>2.8 units to the nearest tenth</h3>

Hope this helps you

6 0
4 years ago
What is the period and midline?
OverLord2011 [107]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\&#10;&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;\bullet \textit{function period}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}&#10;

so if you notice yours \bf \begin{array}{llll}&#10;3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\&#10;&\ \uparrow&\uparrow \\&#10;&B&D &#10;\end{array}

now.. normally the function \bf 3.2cos&\left( \frac{5}{3}\theta \right)
 has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline  up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is 2\pi
so, the new period will be \bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0
3 years ago
Bryan completed a 100-meter race in 11.74 seconds. Luis completed the same race in 11.69 seconds. What was the difference betwee
son4ous [18]

Answer:

\frac{1}{20} of a second

Step-by-step explanation:

We can convert each time into fractions.

11.74 is the same thing as 11 \frac{74}{100}

and 11.69 is the same thing as 11 \frac{69}{100}.

We know that 11 - 11 = 0, so we can focus on the fractions for now.

Let's subtract \frac{69}{100} from \frac{74}{100}.

\frac{74}{100} - \frac{69}{100} = \frac{5}{100}.

We can now simplify \frac{5}{100} by dividing both the numerator and denominator by 5.

\frac{5\div5}{100\div5}  = \frac{1}{20}.

Hope this helped!

6 0
3 years ago
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