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Leto [7]
3 years ago
15

Write 8/9 as a decimal.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
7 0

Answer:

0.88888888888889

Step-by-step explanation:

luda_lava [24]3 years ago
4 0

Answer: 0.88888889

Step-by-step explanation:

Just divide 8/9!

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3 years ago
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padilas [110]
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4 0
3 years ago
4. Professor Kingsfield's class follows very strict grading guidelines. Assume that student averages in Kingsfield's class are n
gtnhenbr [62]

<em>Answer:</em>

<em>For grade A ,a student needs Z score of 2 or above, the required score is</em>

<em> X = 68 + 12Z =92, For grade B, a student needs Z score between 1 and 2 . </em>

<em> The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92, For grade C ,a student needs Z score between -1 and 1 . The  required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80. For the  grade D, a student needs Z score between -2 and -1 . </em>

<em> The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56</em>

Step-by-step explanation:

<em>From the given question, </em>

<em>let the rv X represent student's score.</em>

<em>Z = x - 68/12  ~ N (0,1 )</em>

<em>Now, we know for a standard normal distribution</em>

<em>Thus,</em>

<em>For grade A ,a student needs Z score of 2 or above, the required score is</em>

<em> X = 68 + 12Z =92</em>

<em>For grade B, a student needs Z score between 1 and 2 . </em>

<em> The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92</em>

<em>For grade C ,a student needs Z score between -1 and 1 . </em>

<em> The  required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80</em>

<em>For the  grade D, a student needs Z score between -2 and -1 . </em>

<em> The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56</em>

<em>For student  with score less 44 gets an F.</em>

<em>Note: find an attached image for the graphic sketch of the normal distribution.</em>

3 0
3 years ago
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