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nata0808 [166]
2 years ago
7

Please hlep i don’t get algebra at all

Mathematics
1 answer:
vredina [299]2 years ago
8 0
What do u need help with ?, trigonometry?
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Divide the following polynomial expression.<br><br> (n^4 +5n^3+9n^2) / 9n^3
Serhud [2]
Dhjdjdjdjdjdjndjdjdjdjdjdjjsjdjdjdjd
6 0
3 years ago
Gabriel can't decide whether to get a 16 oz can of Creamy Corn that sells for $1.09, or the 32 oz that's on sale for $1.89. Whic
Finger [1]

Answer:

I would say the 32 oz of corn, because even though they are the same unit price, you get more in the 32 oz of corn.

Step-by-step explanation:

Well, you can set up this equation to find out the unit price for the 16 oz of corn:

$1.09 divided by 16 = $0.06

Same with the 32 oz of corn:

$1.89 divided by 32 = $0.06

7 0
2 years ago
Read 2 more answers
The volume of a cylinder, V, in terms of radius, r,
Igoryamba

Answer:

See explanation

Step-by-step explanation:

Volume of a cylinder = πr²h

Solve for r

V = π * r² * h

r² = V/πh

Find the square root of both sides

r = √V/πh

If height = 6 meters and volume = 300 cubic meters. Find r

r = √V/πh

= √(300/3.14*6)

= √(300/18.84)

= √15.923566878980

r = 3.9904344223381

Approximately,

r = 4 meters

5 0
3 years ago
How do I solve for x and y? ​
slamgirl [31]
8/20=y/25
(0.4=y/25)*25
Y= 10
__________
8/20=(x+4)/15
0.4*15=x+4
6=x+4
X=2
7 0
4 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP WILL GIVE BRAINLIEST
spin [16.1K]

Answer:

c = 7

d = 5

Step-by-step explanation:

Notice that in the first expression, x^c is inside a square root, and only perfect squares can be extracted from it. On the simplified form shown on the right hand side, we have x^3 outside the root and a single "x" left inside. In order for such to happen (x^3 get outside the root) there must have been an x^6 inside the square root. This together with the sole "x" that was left in the root, totals seven factors of x that should have been originally inside the square root:

x^6 * x = x^7  therefore c was a "7"

In the second expression we have a CUBIC root, so only perfect cubes can get extracted from it. Since there is one factor "x" shown in the simplified form (right hand side of the equal sign), that means that it must have been an x^3 (perfect cube) apart from the x^2 that was left inside the root. This makes the original power of x to be a 3 + 2 = 5.

Therefore d = 5

4 0
3 years ago
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