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3 years ago

What goes on the green box?

Mathematics

2 answers:

Lorico [155]3 years ago

8 0

Answer:

2^8

Step-by-step explanation:

i used photomath nfjdjejeje

Varvara68 [4.7K]3 years ago

3 0

2^8 8 put 8 in the box because I smOrt

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The length of a rectangle is 8 inches more than twice its width. The area of the rectangle is 120 square inches. How many inches

Irina-Kira [14]

Answer:

L = 20 inches

Step-by-step explanation:

w = width

L = length

area = 120

W x L = 120

L - 8 = 2W then L = 2W + 8

substitute for L:

W x (2W + 8) = 120

2W² + 8W -120 = 0

(2W - 12)(W + 10) = 0

2W-12 = 0

2W = 12

W = 6

L = 20

7 0

3 years ago

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

$P(M_1\text{ fails or }M_2\text{ fails})=P(M_1\text{ fails})+P(M_2\text{ fails})-P(M_1\text{ and }M_2\text{ both fail})$

by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

The expectation is $\dfrac1p=\dfrac1{p_1+p_2-p_1p_2}$ .

7 0

4 years ago

I need to know how to set up this problem. Please help

ELEN [110]

your total would be $10 and you have 1 variable. so it would be ($2x) for the pounds of veggies, plus the 3.50 for the basket, equals $10. then solve for X from there

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3 years ago

What is the answer to |60| ____|-60|

Anna71 [15]

Answer:

Step-by-step explanation:

Equal too, you are finding the absolute value of both of them which means getting rid of any signs that is attached to them. 60 = 60

8 0

3 years ago

Read 2 more answers

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$

And replacing we got:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

5 0

3 years ago