It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
That would be D
the first 3 = -12x + 24
bur D = -12x - 24
A.) the degrees inside the triangles are 50, 70, and 60. you know because 180-120=60
b.) you know that they are similar triangles because they have the same angle degrees.
im not sure if this is correct but i think it is :)
Answer:
The correct answer is A.
Remember summetric means: made up of exactly similar parts facing each other or around an axis; symmetrical. And the peak or highest part is on the 3.
Hope it helps!!
Answer: (3, 1) :)
Explanation:
-6x + 8y = -10
-4x + y = -11
-32x + 8y = -88
26x = 78
x = 3
-18 + 8y = -10
8y = 8
y = 1
(Also, can I have brainliest please?)
