Answer:
y = 1/2 (2)x
Step-by-step explanation:
Using the equation y = abx , substitute both of your given points into that equation.
2 = ab2 and 4 = ab3 Solve each equation for a.
2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3
Cross multiply: 2b3 = 4b2 Divide both sides by b2
2b = 4 a = 2/4 = 1/2
b = 2
Answer:
95%
Step-by-step explanation:
The empirical rule states that if data follows normal distribution then the percentage of observations falls within one, two and three standard deviation around the mean are
i) 68% falls within one standard deviation
ii) 95% falls within two standard deviation
iii) 99.7% falls within three standard deviation.
Hence 95% of the observations will fall within two standard deviations around the mean if the data follows normal distribution.
Answer:
335.5 in^2
Step-by-step explanation:
The area is a rectangle and a triangle
The area of the rectangle is
A = a*b where a is 11 and b is 25
A = 11*25 =275
The area of the triangle is
A = 1/2 b*h where b is 11 and h is 11
A = 1/2 (11) * 11
A = 60.5
The total area is 275+60.5=335.5
(a) It looks like the ODE is
<em>y'</em> = 4<em>x</em> √(1 - <em>y </em>^2)
which is separable:
d<em>y</em>/d<em>x</em> = 4<em>x</em> √(1 - <em>y</em> ^2) => d<em>y</em>/√(1 - <em>y</em> ^2) = 4<em>x</em> d<em>x</em>
Integrate both sides. On the left, substitute <em>y</em> = sin(<em>t </em>) and d<em>y</em> = cos(<em>t</em> ) d<em>t</em> :
∫ d<em>y</em>/√(1 - <em>y</em> ^2) = ∫ 4<em>x</em> d<em>x</em>
∫ cos(<em>t</em> ) / √(1 - sin^2(<em>t</em> )) d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>
∫ cos(<em>t</em> ) / √(cos^2(<em>t</em> )) d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>
∫ cos(<em>t</em> ) / |cos(<em>t</em> )| d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>
Since we want the substitutiong to be reversible, we implicitly assume that -<em>π</em>/2 ≤ <em>t</em> ≤ <em>π</em>/2, for which cos(<em>t</em> ) > 0, and in turn |cos(<em>t</em> )| = cos(<em>t</em> ). So the left side reduces completely and we get
∫ d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>
<em>t</em> = 2<em>x</em> ^2 + <em>C</em>
arcsin(<em>y</em>) = 2<em>x</em> ^2 + <em>C</em>
<em>y</em> = sin(2<em>x</em> ^2 + <em>C </em>)
(b) There is no solution for the initial value <em>y</em> (0) = 4 because sin is bounded between -1 and 1.
