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jekas [21]
3 years ago
5

Help me!!!! And please provide steps w/ answer!!

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0
1. Box off the squares (which you did)
2. Solve the area of the squares: (10cm x 10cm = 100cm each square)
3. Solve the area of the rectangle that is left: (you would do 40cm x 10cm since the other 10cm went with the square. The rectangle should end up to be 400cm.
4. Add the areas: 100cm + 100cm +400cm = 600cm
600cm is the answer
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Check that x=2 and y=5 is a solution of both equations below:<br> X+2y=12<br> 3x+6y=36 *
melamori03 [73]

Answer:

yes

Step-by-step explanation:

Substitute x = 2 and y = 5 into the left side of the equations and if equal to the right side then they are a solution.

x + 2y = 2 + 2(5) = 2 + 10 = 12 ← True

3x + 6y = 3(2) + 6(5) = 6 + 30 = 36 ← True

Thus x = 2, y = 5 is a solution to both equations

7 0
3 years ago
Read 2 more answers
Apply the distributive property to create an equivalent expression.<br> (m−3+4n)⋅(−8)
Sindrei [870]

Answer:

<h2>-8m + 24 - 32n</h2>

Step-by-step explanation:

The distributive property:

a(b+c)=ab+ac

(m-3+4n)(-8)=(m)(-8)+(-3)(-8)+(4n)(-8)\\\\=-8m+24-32n

7 0
3 years ago
what is the equation in point-slope form of the line that passes through the point (4, "-7)" and has a slope of "-1/4"
Leona [35]

Answer:

y+7=-1/4(x-4) i think

Step-by-step explanation:

6 0
3 years ago
1/3 (q + 3) = 5<br> What is Q? <br> Explain why<br> 1/3 is a fraction
Harrizon [31]

Answer:

q=12.

Step-by-step explanation:

1/3(q+3)=5 can be translated to (q+3)/3=5.

Multiply each side by 3 to get q+3=15.

Subtract 3 from each side to get q=12.

Can you explain what you mean by "Explain why 1/3 is a fraction?"

7 0
3 years ago
Read 2 more answers
what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil
dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
2 years ago
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