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3 years ago

11

What is the best approximation of the sine of 50°?

1 answer:

Gelneren [198K]3 years ago

3 0

The best and most correct answer among the choices provided by your question is the first choice or letter A.

As I calculated it, sine 50 is equivalent to <span>0.2623748537.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Please help will give brainliest!! thank u

Goshia [24]

9514 1404 393

Answer:

(c) 162 cm

Step-by-step explanation:

The centroid divides a median into parts with the ratio 1:2, so RL:LD = 1:2. Then RL:RD = 1:(1+2), and RD = 3RL.

RD = 3·54 cm

RD = 162 cm

5 0

2 years ago

HELP ASSSAP WITH THIS QUESTION

bulgar [2K]

The answer is linear and increasing. look at it.... it goes up.

8 0

3 years ago

the number of cars on equally Arbor Road in here 2007 was 2500 in Year 2014 the number is 4000 calculate the percentage increase

Zepler [3.9K]

Answer:

(4000/2500)100=160%

3 0

3 years ago

How do I solve this proportion??<br> 7/n = 8 / 7

kirill115 [55]

$\frac{7}{n}=\frac{8}{7} \\\\ n=\frac{7*7}{8} \\\\ \boxed{n=\frac{49}{8}}$

7 0

3 years ago

Read 2 more answers

A coin is tossed 600times with the frequencies as:

brilliants [131]

Answer:

see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

$let \: E_1 \: and \: E_2 \: be \: the \: events \: of \: getting \: a \: head$

and of getting a tail respectively.

then,

$1) \: P \: (getting \: a \: head) = \: P \: (E_1)$

$\longrightarrow \: \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{342}{600} = \frac{57}{100}$

$\longrightarrow \: 0.57$

$\red{ \rule{150pt}{3pt}} \:$

$2) P (getting \: a\: tail) =P (E_2)$

$\longrightarrow \: \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{258}{600} = \frac{43}{100}$

$\longrightarrow \: 0.43$

6 0

2 years ago