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bonufazy [111]
3 years ago
8

Answer two questions about Equations A and B: A.5x=20 \ B.x=4 ​ 1) How can we get Equation B from Equation A? Choose 1 answer: (

Choice A) Multiply/divide both sides by the same non-zero constant (Choice B,) Multiply/divide both sides by the same variable expression (Choice C) Add/subtract the same quantity to/from both sides (Choice D) Add/subtract a quantity to/from only one side
Mathematics
1 answer:
romanna [79]3 years ago
3 0

Answer:

Multiply/divide both sides by the same non-zero constant

Step-by-step explanation:

5x = 20

Divide each side by 5

5x/5 = 20/5

x = 4

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A test consists of 20 true/false questions. If a student guesses on each question, what Is the probability of getting exactly 15
k0ka [10]

Answer:

50%

Step-by-step explanation:

due to the fact that its true/false questions, so that means when you answer you have 2 choices. a 50/50 chance of getting them right or wrong

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Thomas earns 15 per hour if he recurved a 10% per hour pay increase how much does Thomas now make per hour
erica [24]

Answer:

He now makes 16.50 per hour

Step-by-step explanation:

15.00 x .10 = 1.50

15.00 + 1.50 = 16.50

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3 years ago
A nut wholesaler sells a mix of peanuts and cashews. He charges $2.80 per pound for peanuts and $5.30 per pound for cashews. If
Len [333]

Answer: 20 pounds of peanuts and 80 pounds of cashews.

5 0
3 years ago
Read 2 more answers
How do ypu slove dis? <br>y^2(q-4) - c(q - 4)
Annette [7]
<span><span> y2(q-4)-c(q-4)</span> </span>Final result :<span> (q - 4) • (y2 - c) </span>

Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span><span> ((y2) • (q - 4)) - c • (q - 4) </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> y2 • (q - 4) - c • (q - 4) </span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>     Pull out     q-4 

After pulling out, we are left with : 
      (q-4) • (<span> y2</span>  *  1 +( c  *  (-1) ))

Trying to factor as a Difference of Squares :

<span> 3.2 </span>     Factoring: <span> y2-c</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : <span> y2  </span>is the square of <span> y1 </span>

Check :<span> <span> c1  </span> is not a square !! 
</span>Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :<span> (q - 4) • (y2 - c) </span><span>
</span>
4 0
3 years ago
In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

  EF

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0
2 years ago
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