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3 years ago

Does anyone know the answer

Mathematics

2 answers:

Allushta [10]3 years ago

7 0

Answer:

The y-intercept is at -3 and the slope is 7/4

Step-by-step explanation:

arsen [322]3 years ago

6 0

Answer:

i cant see the photos

Step-by-step explanation:

sorry talaga

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What is the product of 33 and j

Softa [21]

Answer:

It would be 33j, Product means multiplication, so if you multiply 33 times j, you get 33j

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3 years ago

Fill in the blank with the recursive function. Be sure to include the starting point.

erik [133]

Answer:

The recursive function that represents the number of books Ashley has at any time is

$a_n=a_{n-1}-n$

starting at

$a_1=100$

Step-by-step explanation:

Ashley has 100 books that she wants to give away at the rate of n books per week.

So,

$a_1=100\\ \\a_2=100-n=a_1-n\\ \\a_3=a_2-n\\ \\...\\ \\a_n=a_{n-1}-n$

Thus, the recursive function that represents the number of books Ashley has at any time is

$a_n=a_{n-1}-n$

starting at

$a_1=100$

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4 years ago

Rewrite the equation y - 8 = 2(x + 4) into slope-intercept form (y = mx + b).

MAVERICK [17]

Answer:

y=2x+16 is the slope intercept form.

Step-by-step explanation:

7 0

3 years ago

92. How much material was required for

erma4kov [3.2K]

answer:92+92=184 184×5=920

5 0

3 years ago

A woman is emptying her aquarium at a steady rate with a small pump. The water pumped to a 12-in.-diameter cylindrical bucket, a

Temka [501]

Answer:

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

Step-by-step explanation:

Given that,

The diameter of cylindrical bucket = 12 in.

Depth is increasing at the rate of = 4.0 in per minutes.

i.e $\frac{dh_1}{dt}=4$

$h_1$ is depth of the bucket.

The volume of the bucket is V = $\pi r^2 h$

$=\pi \times 6^2\itimes h_1$

$\therefore V=36\pi h_1$

Differentiating with respect yo t,

$\frac{dV}{dt}=36\pi \frac{dh_1}{dt}$

Putting $\frac{dh_1}{dt}=4$

$\therefore\frac{dV}{dt}=36\pi\times 4$

The rate of volume change of the bucket = The rate of volume change of the aquarium .

Given that,The aquarium measures 24 in × 36 in × 18 in.

When the water pumped out from the aquarium, the depth of the aquarium only changed.

Consider h be height of the aquarium.

The volume of the aquarium is V= ( 24× 36 ×h)

V= 24× 36 ×h

Differentiating with respect to t

$\frac{dV}{dt}=24\times 36 \times \frac{dh}{dt}$

Putting $\frac{dV}{dt}=36\pi\times 4$

$36\pi\times 4= 24\times 36\times \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt}=\frac{36\pi \times 4}{24\times 36}$

$\Rightarrow \frac{dh}{dt}=\frac{11}{21}$

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

7 0

4 years ago