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ki77a [65]
2 years ago
5

Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different way

s can the four students be arranged to take a picture?
Show your work, please :')
Mathematics
2 answers:
yulyashka [42]2 years ago
8 0

Answer:

  • 24 ways

Step-by-step explanation:

<u>This is the permutation of 4:</u>

  • 4P4 = 4! = 1*2*3*4 = 24 ways
user100 [1]2 years ago
7 0

\huge\qquad  \mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}

✶⊶⊷⊶⊷❍❁❥❀❥❁❍⊶⊷⊶⊷✶

Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different ways can the four students be arranged to take a picture

so we have to find the permutation of 4

  • 4×3×2×1
  • 24

.°. In 24 different ways can the four students be arranged to take a picture

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Semmy [17]

Answer:

\boxed{x = 7}

Step-by-step explanation:

75 = 11x-2 <u><em>(Corresponding angles are equal)</em></u>

11x -2 = 75

Adding 2 to both sides

11x = 75+2

11x = 77

Dividing both sides by 11

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5 0
3 years ago
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How do you write the algebraic expression 6 less than the quotient of 32 and a number y
masha68 [24]

Answer:

( 32/y ) - 6

Step-by-step explanation:

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this means that 6 is going to be subtracted from (32/y)

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4 0
3 years ago
X^2 + 2x + 5 find the zeros
Dvinal [7]

Answer:

Step-by-step explanation:

This is what I got

8 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
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OlgaM077 [116]

Answer:

The correct answer is (x-y)

Step-by-step explanation:

x^2-xy

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3 years ago
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