Explain for both problems and tell me the work that comes with it please and thank you

Mathematics

1 answer:

Anton [14]3 years ago

3 0

Problem 33

Use the distributive property on the side containing parentheses of each expression and compare it to the other side.

a) 3(5a + 3) = 15a + 9 not equal to 15a + 6

b) 2(7b - 2) = 14b - 4 not equal to 14b + 4

c) 5(2c + 3) = 10c + 15 not equal to 7c + 8

d) 3(d + 5/3) = 3d + 5 which is equal to 3d + 5

Answer for problem 33: d)

Problem 34

Use a proportion. Let the unknown number of bowls be x. The proportion is made up of two ratios that are set equal to each other. Set each ratio as a ratio of the number of avocados per bowls of guacamole. 3 avocados per 1 bowl (3/1) equals 17 avocados per x bowls (17/x).

$\dfrac{3}{1} = \dfrac{17}{x}$

$3x = 17 \times 1$

$3x = 17$

$x = \dfrac{17}{3}$

$x = 5 \dfrac{2}{3}$

Answer: 17/3 full bowls which is the same as 5 2/3 full bowls.

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Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .