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kkurt [141]
3 years ago
11

Find the value of (X) The subject is polygons.

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Please delete this answer.

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Of the 200 packages of bagels sold 15 of them were sesame seed bagels. What percent of the bagel packages sold are sesame seed b
Paladinen [302]

Answer:

.015%

Step-by-step explanation:

Hope it helps


~CoCo

6 0
3 years ago
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Shelly and Mickelle are making a quilt. They have a piece of fabric that measures 48 inches by 168 inches.
irinina [24]

Answer:

(a) The largest square side is 24 inches

(b) No. of pieces are 14

Step-by-step explanation:

As per the question:

The dimensions of the fabric are 48 in\times 168 in

(a)To calculate the side length of the largest square piece, we need to find the Greatest Common Factor (GCF) of the dimensions as:

48 = 2\times 2\times 2\times 2\times 3

168 = 2\times 2\times 2\times 3\times 7

Therefore,

The GCF of the dimensions = 48 = 2\times 2\times 2\times 3 = 24

Therefore, the largest side of  a square that can be cut from the fabric is 24 inches.

(b) The no. of pieces of 24 inches that can be cut from the fabric can be given as:

No. of pieces = \frac{Total\ Area}{Area\ of\ largest\ square}

No. of pieces = \frac{48\times 168}{24\times 24} =  14

7 0
3 years ago
Read 2 more answers
Stella needs fencing for the perimeter of a
Crazy boy [7]

Answer:

\boxed{Fencing \: need \: to \: buy \: for \: the \: entire \: perimeter = \frac{40}{3}  \: yards}

Step-by-step explanation:

Length of rectangular garden (l) = 16 feet

Width of rectangular garden (w) = 4 feet

3 \: feet = 1 \: yard \\  \\   1 \: feet =  \frac{1}{3}  \: yard

\\ =  > Perimeter \: of \: rectangular \: garden = 2(l + w) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  = 2(16 + 4) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \: = 2 \times 20 \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \:  = 40 \: feets \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \:  =40 \times  \frac{1}{3}  \: yards \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \:  = \frac{40}{3}  \: yards

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3 years ago
What is the solution to the system of equations?
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A system of equation are a set or collection of equations altogether at once
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