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Taya2010 [7]
3 years ago
12

For each compound below, identify any polar covalent bonds and indicate the direction of the dipole moment using the symbols δ +

and δ-.
(a) HBr
(b) HCI
(c) H2O
(d) CH40
Computers and Technology
1 answer:
Lorico [155]3 years ago
5 0

Answer:

H-Br bond is polar, hydrogen is partly positive and bromine is partly negative

H-Cl bond is polar, hydrogen is partly positive and bromine is partly negative

O-H bond in water is polar, hydrogen is partly positive and oxygen is partly negative

C-O bond in CH40 is polar, carbon is partly positive and oxygen is partly negative

Explanation:

A molecule possess a dipole moment when there is a large difference in electro negativity between two bonding atoms in the molecule.

The presence of dipole moments introduces polarity to the molecule. In all the molecules listed in the answer, the shared electron pair of the bond is closer to the more electronegative atom causing it to be partially negative while the less electronegative atom in the bond is partially positive.

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Write a calculator program that keeps track of a subtotal like real calculators do. Start by asking the user for an initial numb
Taya2010 [7]

Answer:

num1 = float(input("Enter the first number: "))

while True:

   print("Add, Subtract, Multiply, Divide, or Quit ?")

   choice = input("Your choice is: ")

   if choice == "Quit":

       break

   num2 = float(input("Enter the second number: "))

   if choice == "Add":

       num1 += + num2

       print("The subtotal is: " + str(num1))

   elif choice == "Subtract":

       num1 -= num2

       print("The subtotal is: " + str(num1))

   elif choice == "Multiply":

       num1 *= num2

       print("The subtotal is: " + str(num1))

   elif choice == "Divide":

       num1 /= num2

       print("The subtotal is: " + str(num1))

print("The final result is: " + str(num1))

Explanation:

Ask the user for the first number

Create a while loop that iterates until specified condition occurs inside the loop

Ask the user for the operation or quitting

If the user chooses quitting, stop the loop. Otherwise, get the second number, perform the operation and print the subtotal

When the loop is done, the user enters Quit, print the final value result

8 0
3 years ago
Intellectual property piracy has gotten a small boost from the increasing availability of counterfeit goods through Internet cha
Aliun [14]

Answer:

The answer is "Option B".

Explanation:

Intellectual property is protected by law in which property, copyright, and trademarks, are uses, that enable you to gain individuals' popularity or personally benefit according to what they create.

  • It is a program that helps to create an environment, in which imagination and technology are used.
  • It will change the growth by striking a balance between innovator rights and wider public interest.
3 0
3 years ago
Where are the values the computer is directly working with at a particular moment in time stored?
pav-90 [236]

On the CPU register (?) The CPU registers are registers with small amounts of high-speed memory contained within the CPU. They are used by the processor to store small amounts of data that are needed during processing

Hope this helps and that you have a good day

4 0
3 years ago
Read one positive integer n. Then create an n X n two-dimensional array and write the code that stores integers from 1 to n2 as
marysya [2.9K]

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main(String[] args) {

    int n;

    Scanner input = new Scanner(System.in);

 System.out.print("Size of array: ");

 n = input.nextInt();

 int count = 1;

 int[][] arr = new int[n][n];

 for(int i = 0; i<n;i++){

     for(int j = 0; j<n;j++){

         arr[i][j] = count;

         count++;      }  }

 for(int i = 0; i<n;i++){

     for(int j = 0; j<n; j++){

         System.out.printf(arr[i][j]+" ");      }

     System.out.println();  } }}

Explanation:

This declares the size of the array

    int n;

    Scanner input = new Scanner(System.in);

This prompts the user for size of array

 System.out.print("Size of array: ");

This gets input for size of array

 n = input.nextInt();

This initializes the array element to 1

 int count = 1;

This creates a 2d array

 int[][] arr = new int[n][n];

This iterates through the rows

 for(int i = 0; i<n;i++){

This iterates through the columns

     for(int j = 0; j<n;j++){

This populates the array

         arr[i][j] = count;

         count++;      }  }

The following nested loop prints the array elements

 for(int i = 0; i<n;i++){

     for(int j = 0; j<n; j++){

         System.out.printf(arr[i][j]+" ");      }

     System.out.println();  } }}

8 0
3 years ago
Write a program that reads the data from rawdata_2004.txt into a dictionary whose keys are country names and whose values are pe
san4es73 [151]

Answer:

import re

def country_capita():

   #opens file

   file=open("inputfile.txt", "r")

   dictionary=dict()

   #reads line by line

   for line in file.readlines():

       # substitutes for multiple space a single space

       line = re.sub(r"[\s]{2, }", ' ', line)

       list=[]

       #splits line on space

       list=line.split(" ")

       #put into dictionary

       dictionary[list[1]]=list[2]

#   get input

   while True:

       choice=input("Enter the country name or quit to exit: ")

       if choice=="quit":

           break

       elif choice in dictionary.keys():

           print(dictionary[choice])

       else:

           print("Invalid Country")

country_capita()

Explanation:

Using python to code this program. First we, (line 1) import the re module which offers us a set of functions that allows us to search a string for a match. ((line 2) Next we define a function country_capita() that will open rawdata_2004.txt, read the information within line by line and create a dictionary list. The we create a while loop with conditional statements that prompt the user to enter country names, print the corresponding values and stops when the user enters quit.

7 0
3 years ago
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