C= 3.14d
C= 3.14 x 9.06
C= 28.45
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

By substitution:

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

Zero Product Property:

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
Answer:
simplify the expression: 6x+5y
Step-by-step explanation: