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kirill [66]
3 years ago
7

Christine is interested in buying a new backpack. She compares the price and volume of several backpacks. Christine finds that t

he relationship between price and volume can be described by the following least square regression line:
Predicted Price = 890 - 105(Backpack Volume).
What is the slope of Christine’s data?
Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

It’s 90 pretty sure

Step-by-step explanation:

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Parallel and perpendicular worksheet
vlada-n [284]

Answer:

i used to know how to do this but i forgot sorry hope someone helps

Step-by-step explanation:

Good Luck!!

5 0
3 years ago
Answer choces<br> 1. 55%<br> 2.45%<br> 3.25%
Alika [10]

Answer: 2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the following sum?<br>(please show how you worked it out)
AleksAgata [21]

Answer:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Step-by-step explanation:

Let's start by breaking down each of the radicals:

\sqrt[3]{16x^3y}

Since we're dealing with a cube root, we'd like to pull as many perfect cubes out of the terms inside the radical as we can. We already have one obvious cube in the form of x^3, and we can break 16 into the product 8 · 2. Since 8 is a cube root -- 2³, to be specific, we can reduce it down as we simplify the expression. Here our our steps then:

\sqrt[3]{16x^3y}\\=\sqrt[3]{2\cdot8\cdot x^3\cdot y}\\=\sqrt[3]{2} \sqrt[3]{8} \sqrt[3]{x^3} \sqrt[3]{y} \\=\sqrt[3]{2} \cdot2x\cdot \sqrt[3]{y} \\=2x\sqrt[3]{2}\sqrt[3]{y}

We can apply this same technique of "extracting cubes" to the second term:

\sqrt[3]{54x^6y^5} \\=\sqrt[3]{2\cdot27\cdot (x^2)^3\cdot y^3\cdot y^2} \\=\sqrt[3]{2}\sqrt[3]{27} \sqrt[3]{(x^2)^3} \sqrt[3]{y^3} \sqrt[3]{y^2}\\=\sqrt[3]{2}\cdot 3\cdot x^2\cdot y \cdot \sqrt[3]{y^2} \\=3x^2y\sqrt[3]{2} \sqrt[3]{y}

Replacing those two expressions in the parentheses leaves us with this monster:

2(2x\sqrt[3]{2}\sqrt[3]{y})+4(3x^2y\sqrt[3]{2} \sqrt[3]{y})

What can we do with this? It seems the only sensible thing is to look for terms to factor out, so let's do that. Both terms have the following factors in common:

4, \sqrt[3]{2} , x

We can factor those out to give us a final, simplified expression:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Not that this is the same sum as we had at the beginning; we've just extracted all of the cube roots that we could in order to rewrite it in a slightly cleaner form.

6 0
3 years ago
Simon caught 5 striped fish. Each one weighed the same number of pounds.Then he caught another fish that weighted 7 pounds. Writ
nekit [7.7K]
5x + 7 

5x represents the weight of the 5 striped fish. 

7 represents the fish that weighs 7 pounds. 
8 0
4 years ago
Read 2 more answers
I have no idea how to do this. I can’t cooperate with the imaginary number, please help me
NeTakaya

Answer:

Step-by-step explanation:

This is a third degree polynomial because we are given three roots to multiply together to get it.  Even though we only see "2 + i" the conjugate rule tells us that 2 - i MUST also be a root.  Thus, the 3 roots are x = -4, x = 2 + i, x = 2 - i.

Setting those up as factors looks like this (keep in mind that the standard form for the imaginary unit in factor form is ALWAYS "x -"):

If x = -4, then the factor is (x + 4)

If x = 2 + i, then the factor is (x - (2 + i)) which simplifies to (x - 2 - i)

If x = 2 - i, then the factor is (x - (2 - i)) which simplifies to (x - 2 + i)

Now we can FOIL all three of those together, starting with the 2 imaginary factors first (it's just easier that way!):

(x - 2 - i)(x - 2 + i) = x^2-2x+ix-2x+4-2i-ix+2i-i^2

Combining like terms and canceling out the things that cancel out leaves us with:

x^2-4x+4-i^2

Remembr that i^2=-1, so we can rewrite that as

x^2-4x+4-(-1) and

x^2-4x+4+1=x^2-4x+5

That's the product of the 2 imaginary factors.  Now we need to FOIL in the real factor:

(x+4)(x^2-4x+5)

That product is

x^3-4x^2+5x+4x^2-16x+20

which simplifies down to

x^3-11x+20

And there you go!

4 0
4 years ago
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