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Nata [24]
3 years ago
6

50x1= what is the answer?​

Mathematics
2 answers:
ser-zykov [4K]3 years ago
8 0
The answer is 50. 1 times any number is that number.
mote1985 [20]3 years ago
3 0

Answer: 50

Step-by-step explanation:

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What is the prime factorization of 16?
Georgia [21]

Answer:

the prime factorization of 16 is 2^4 (because 2*2*2*2 is 16, and those twos cannot be split into anymore numbers)

Step-by-step explanation:

brainliest please?

7 0
4 years ago
Read 2 more answers
Help me pls ASAP I need it in 5mins​
Svetradugi [14.3K]

Answer:

74 cars

Step-by-step explanation:

14(2) + 4x = 324

28 + 4x = 324

4x = 296

x = 74

6 0
3 years ago
On the day Alexander was born, his father invested $5000in an account with a 1.2% annual growth rate. Write a function, A(t) tha
stepladder [879]

Answer:

Equation:  A(t)=5000(1.012)^n

Worth more in 32 yr than in 17 yr by:  $1199.92

Step-by-step explanation:

THe compound growth formula is:

F=P(1+r)^n

Where

F is the future amount (here, A(t))

P is the initial amount, here 5000

r is the rate of growth in decimal, 1.2% = 1.2/100 = 0.012

n is the time in years

Thus, we can say the function would be:

A(t)=5000(1+0.012)^n\\A(t)=5000(1.012)^n

Now, we want how much more it will be worth when 17 years and 32 years. We find the future amount, A(t), when n= 17 and n = 32 and find the difference. Shown below:

A(t)=5000(1.012)^n\\A(17)=5000(1.012)^{17}\\=6124.05

and

A(32)=5000(1.012)^{32}\\=7323.97

So, it will be worth more by:

7323.97 - 6124.05 = $1199.92

3 0
3 years ago
Suppose that 500 parts are tested in manufacturing and 10 are rejected.
alexdok [17]

Answer:

a) z=\frac{0.02 -0.03}{\sqrt{\frac{0.03(1-0.03)}{500}}}=-1.31  

p_v =P(Z  

If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of rejected items is less than 0.03.  

b) We can use a 95 percent upper confidence interval.

On this case we want a interval on this form : (-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})

So the critical value would be on this case Z_{\alpha}=1.64 and we can use the following excel code to find it: "=NORM.INV(1-0.05,0,1)"

We found the upper limit like this:

0.02+1.64\sqrt{\frac{0.02 (1-0.02)}{500}}=0.03026

And the interval would be: (-\infty,0.03026)

And since our value (0.02) is contained in the interval We fail to reject the hypothesis that p=0.03

Step-by-step explanation:

Part a

Data given and notation  

n=500 represent the random sample taken

X=10 represent the number of objects rejected

\hat p=\frac{10}{500}=0.02 estimated proportion of objects rejected

p_o=0.03 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that 70% of adults say that it is morally wrong to not report all income on tax returns.:  

Null hypothesis:p=0.03  

Alternative hypothesis:p < 0.03  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.02 -0.03}{\sqrt{\frac{0.03(1-0.03)}{500}}}=-1.31  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one tailed left test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of rejected items is less than 0.03.  

Part b

We can use a 95 percent upper confidence interval.

On this case we want a interval on this form : (-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})

So the critical value would be on this case Z_{\alpha}=1.64 and we can use the following excel code to find it: "=NORM.INV(1-0.05,0,1)"

We found the upper limit like this:

0.02+1.64\sqrt{\frac{0.02 (1-0.02)}{500}}=0.03026

And the interval would be: (-\infty,0.03026)

And since our value (0.02) is contained in the interval We fail to reject the hypothesis that p=0.03

3 0
3 years ago
Write the equation of a line with a slope of -2 and a y-intercept of 5. (2 points)
Yuri [45]

Answer:

-2x+y=5

Step-by-step explanation:

I got this answer on Desmos Graphing Calculator.

the other ones don't make sense with what you were asking for. sorry if this isn't adequate.

6 0
3 years ago
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