ANSWER:
- x – 3y = 2 ...(1)
- 2x – 6y = 6 ...(2)
On solving eq(1), we get
Plug the value of x in eq(2)
- 2x – 6(x - 2/3) = 6
- 2x – 2(x – 2) = 6
- 2x – 2x + 4 = 6
- 0 = 6 – 4
- 0 ≠ 2
So, given system of equations is not correct.
Answer:
D: 11
Step-by-step explanation:
mark brainliest
Answer: y=3/4x+3/2
Step-by-step explanation:
Let's solve for y.
3x−4y+6=0
Step 1: Add -3x to both sides.
3x−4y+6+−3x=0+−3x
−4y+6=−3x
Step 2: Add -6 to both sides.
−4y+6+−6=−3x+−6
−4y=−3x−6
Step 3: Divide both sides by -4.
−4y/−4= −3x−6/−4
y=3/4x+3/2
Answer:
-5 i think, sorry if its worng
Step-by-step explanation: