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iren [92.7K]
3 years ago
11

PLEASE HELP i have no clue what the answer is

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

y=2/3x+19/3

Step-by-step explanation:

Use this equation y-y1=m(x-x1) and plug the numbers in

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timurjin [86]
The answer to this question is true
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3 years ago
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iogann1982 [59]
Graph these numbers and then connect at the end.


3. y (6,-3). x (2,-4) z (5,-7)

4. U (5,4). T (5,1) S (1,0) V(-3,4)

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7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B8a%5E%7B-5%7Db%5E%7B4%7D%20%7D%7B12a%5E%7B-6%7Db%5E%7B-2%7D%20%7D%29" id="TexForm
Oxana [17]

Answer:

→ \frac{8 {a}^{( - 5) } {b}^{(4)}  }{12 {a}^{( - 6)} {b}^{( -  2)}  }  =  \frac{2 {a}^{(6 - 5)}{b}^{(4 + 2)} }{3}   =  \boxed{ \frac{2}{3}a {b}^{6} }✓ \\

  • <u>(2/3)ab⁶</u> is the right answer.
6 0
3 years ago
How to do 3(x-2)= -6
nasty-shy [4]

Answer:

3×x -3×2=-6

or,3x-6=-6

or,3x=-6+6

or,x=0/3

therefore=x =1 answer

8 0
3 years ago
Read 2 more answers
The test results for a class with 24 students are normally distributed with a mean of 82 and a standard deviation of 8.9. What i
alekssr [168]

Answer:

The value is  P( X >  80 ) =  0.58901

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  24

    The mean is  \mu  =  82  

    The standard deviation is  \sigma  =  8.9

   

Generally the  probability that a randomly chosen student earned a B or higher on the test (score of 80 or higher )  is mathematically represented as

         P( X >  80 ) =  P( \frac{ X - \mu }{\sigma }  > \frac{ 80 - 82 }{ 8.9 } )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

 =>  P( X >  80 ) =  P(Z   > -0.225  )

From the z table  the area under the normal curve to the right  corresponding to    -0.225  is  

     P(Z   > -0.225  )   =   0.58901

=>   P( X >  80 ) =  0.58901

5 0
3 years ago
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