Question

Which equation shows y+15=3x in standard form?

Answer 1

Answer:

Option A is correct.

$15x-5y=1$

Step-by-step explanation:

The standard of any equation is in the form of:

$Ax+By = C$

Given the equation: $y+\frac{1}{5} = 3x$

Multiply both sides by 5 we get;

$5y+1 = 15x$

Subtract 5y from both sides we get;

$1 = 15x-5y$

or

$15x-5y=1$

Therefore, the equation $y+\frac{1}{5} = 3x$ in standard form is $15x-5y=1$