V = (1/4)(π* d² * h)
<span>V = (1/4)(π * 10² * 12) </span>
<span>V = (1/4)(1200π) </span>
<span>V = 300π </span>
<span>[ V ≈ 942 cubic units . . . . . to 3 s.f. ] </span>
<span>V ≈ 942 cubic units
</span>
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
7x⁷+2x⁻⁴+3 is a Polynomial
Step-by-step explanation:
I'm sorry I can't explain how I got the answer by hand. I graphed the Equation.
Answer: b) The data is spread close to the mean
Step-by-step explanation: Theoretically, when the standard deviation of a statistical data is large or high, it simply means that the values in such statistical data set are farther away from the mean, On the other hand when the standard deviation is small or low, it simply means that the values of such statistical data are close to the mean of those data on average.
Therefore Judy's low standard deviation for her project simply indicates that her statistical data set is spread close to the mean.
Answer:
ammmm walang lumabas
Step-by-step explanation:
sorry talaga po sa susunod nalang
