Answer:
The sum of two numbers is 14 and their difference is 10
Step-by-step explanation:
"2 numbers (x and y)
x+y = 14
and x-y + 10
If you each equation by positive 2, one gets 2x+2y = 28 and 2x-2y = 20
The 'y-terms' cancel out or equal zero when adding, so 4x = 48, divide by 4 on each side and x or the first number equals 12.
Plug 12 back into the equation for 'x' and subtract 12 on both sides so that y=2
The difference of 12-2=10 and the addition of 12 and 2 equals 14"
hopes this helps
Answer:
The answer is C, the coefficient.
Answer:
71
Step-by-step explanation:
Remember to always follow PEMDAS as well as the left -> right rule. While you do not need PEMDAS for this expression specifically, it is always good to know it. PEMDAS is the order of operations:
PEMDAS =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
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First, solve the parenthesis:
(6 - 3) = 3
Next, simplify, by adding:
36 + 32 + 3 =
68 + 3 = 71
71 is your answer.
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Answer:
<u>There are 17 terms in the sequence</u>
Step-by-step explanation:
<u>Arithmetic Sequence
</u>
An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:
Where an is the nth term, a1 is the first term, and r is the common difference.
In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:
We need to express r as an improper or proper fraction:
Substituting:
n=17
There are 17 terms in the sequence
