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andrew11 [14]
3 years ago
15

what is the probability that a number selected at random from the set {2,3,7,12,15,22,72,108} will be divisible by both 2 and 3?

Mathematics
1 answer:
evablogger [386]3 years ago
7 0
First, look at how many numbers are divisible by 2 and 3. 
12,72, and 108 and are all divisible by both 2 and 3. That makes 3 out of 8 numbers.
Depending on what form you have to put the probability, that makes it 3:8, 3 out of 8, or 37.5% probability.
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Simora [160]

Answer:

The probability is 0.31

Step-by-step explanation:

In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.

Firstly, we calculate the standard score of $86 using the mean and the standard deviation.

Mathematically;

z-score = (x-mean)/SD

where x = 86, mean = 84 and SD = 4

z-score = (86-84)/4 = 2/4 = 0.5

Hence, we want to calculate P(z ≥ 0.5)

Using standard table

P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854

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alexandr402 [8]

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marysya [2.9K]

Answer: \sin \theta=\frac{-45}{53}

Step-by-step explanation:

Since we have given that

\cos\theta=\frac{28}{53}

And we know that θ is in the Fourth Quadrant.

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As we know the "Trigonometric Identity":

\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}

It must be negative due to its presence in Fourth quadrant.

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7 0
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4 0
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Misha Larkins [42]
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Andrea payed $14.02 for a pair of jeans
Hopes this helps you!

6 0
3 years ago
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