Answer:
1. The population of interest is all city goverments in the U.S.
5. The parameter of interest is the proportion of the city goverments in the U.S. that provide electricity to their residents.
Step-by-step explanation:
Hello!
Missing questions:
Which of the following is true? Select all that apply.
- The population of interest is all city governments in the U.S.
- The population of interest is the 192 cities.
- The population of interest is all city governments that provide utilities to their residents.
- The population of interest is 6.25%
- The parameter of interest is the proportion of the city governments in the U.S. that provide electricity to their residents.
- The parameter of interest is 6.25%
- The population of interest is the 20 counties.
- The parameter of interest is the list of all counties in the U.S.
The objective of this essay is to test utilities provided by city governments, for this a sample of 20 counties was taken then contacted each city of them counting how many of them provided utilities to their residents, finding out that 12 out of 192 cities (6.25%) provided electricity to their residents.
The study variable is:
X: Number of city governments that provide utilities (electricity) to their residents, in a sample of 192.
The population of the study is the city governments in the U.S.
And the parameter of interest is the population proportion of city governments in the U.S. that provide electricity to their residents.
I hope it helps!
Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be
Hence, the mean and standard deviation are 567.2 and 89.88 resp.
Answer:
The answer to your question is: y = -1/9 x - 40/9
Step-by-step explanation:
Data
A (-4 , -4)
B (5, -5)
Formula
m = (y2 - y1) / (x2 - x1)
y = mx + b
(y - y1) = m(x - x1=
Process
m = (-5 + 4) / (5 + 4)
m = -1 / 9
( y +4) = -1/9 (x + 4)
y + 4 = -1/9 x - 4/9
y = -1/9 x - 4/9 - 4
y = -1/9 x - 4/9 - 36/9
y = -1/9 x - 40/9
Hi there!
There is 1 3/4 doses, each with 1/4 teaspoons.
Could you please Brainliest me?
d = r * t
d/t = r
-35.75 / 3.25 = r
-11 = r
r = -11 ft / min
d = r*t
d = -11 ft/min * 1 min
d = -11 ft
The probe is 11 feet below sea level after 1 minute
