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3 years ago

Isaac creates a scatter plot showing the association between the height and weight of his male

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

8 0

Answer:

Step-by-step explanation:

Given

w is the classmate's weight in pounds

h is the height

The general formula for the expression is y = MX+c where

m is the slope

c is the intercept

M is the change in y to change in x

Comparing with the given equation

w = 6.5h - 275, we will see that the slope of the equation is 6.5 and can be expressed as the change in the classmate's height to the classmate's weight

slope = dh/dw = 6.5

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What is the LCM 18,10,12? yeah

Karo-lina-s [1.5K]

Answer:

The LCM of 10, 12, and 18 is 180.

HOPE THIS HELPED!!!!!!!!!!!!XDDDDDDDD

4 0

3 years ago

Read 2 more answers

At a local fitness center, members pay a $10 membership fee and $5 for each aerobics class. Nonmembers pay $6 for each aerob

sveta [45]

One way to solve it is writing two equations based on the info so

y = 5x + 10 for members
y = 6x for nonmembers

(the + 10 isn't included in the second equation because nonmembers won't pay a membership fee)

and to find their intersection point (where the values will be the same), you just set them equal to each other:

5x + 10 = 6x

subtract 5x

x = 10 classes

7 0

3 years ago

Solve for x.<br><br> (x−2)^2+2=38<br><br> x= ___ or x= ___

Elan Coil [88]

Answer:

$x \: = \: \boxed{ \bold{ - 4 }}\: \: \text{or} \: \: x \: = \: \boxed{ \bold{ 8}}$

Step-by-step explanation:

$(x \: - \: 2 {)}^{2} \: + \: 2 \: = \: 38$

${x}^{2} \: - \: 4x \: + \: 4 \: + \: 2 \: = \: 38$

${x}^{2} \: - \: 4x \: + \: 6 \: = \: 38$

${x}^{2} \: - \: 4x \: + \: 6 \: - \: 38 \: = \: 0$

${x}^{2} \: + \: 4x \: - \: 8x \: - \: 32 \: = \: 0$

$x \: \times \: (x \: + \: 4) \: - \: 8(x \: + \: 4) \: = \: 0$

$(x \: + \: 4) \: \times \: (x \: - \: 8) \: = \: 0$

When it happens that the product of the factors is the same as zero. It is divided into two possible cases.

$x \: + \: 4 \: = \: 0 \\ x \: - \: 8 \: = \: 0$

We solve the two equations:

$x \: = \: - 4 \\ x \: = \: 8$

<h2>Answer: </h2>

$x \: = \: - 4 \\ x \: = \: 8$

<h3><em><u>MissSpanish</u></em></h3>

6 0

2 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

A box of granola bars contains 3 chocolate chip bars, 2 peanut butter bars, 1 lemon bar, and 4 raisin bars. Iesha will randomly

ella [17]

Answer:

2/45

Step-by-step explanation:

Note this selection is done without replacement hence after each selection sample size will reduce

Given data

Samples 3 chocolate chip bars,

2 peanut butter bars,

1 lemon bar, and

4 raisin bars

Sample size S= [3+2+1+4]= 10

Probability that first selection is lemon = 1/10

Probability that second selection is raisin = 4/9

Hence the probability that the first bar Iesha selects will be lemon and the second will be raisin= 1/10*4/9

= 4/90= 2/45

3 0

3 years ago