Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
-34(x+2)=6
Distribute the -34
x(-34) +2(-34)=6
-34x-68=6
Add 68 to both sides
-34x-68+68=6+68
-34x=74
Devide both sides by -34
x=-37/17
x= 2 3/17
Answer:
i think 1
remember like this: y=mx+b
m is slope
b is y intercept
You need to find x so that then you can do it and you didn’t share a answer so how are we supposed to know??
