Answer:
Step-by-step explanation:
the mean would be appropriate measure of center to describe the data shown in the histogram because the data is symmetrical.A symmetric histogram is a distribution in which the 2 halves appear to be the same on both sides.
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
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Answer: None
Step-by-step explanation:
If A=4, say for example, our list becomes: 3/4, 4/5, 75%.
This in decimal form becomes: 0.75, 0.8, 0.75 which is clearly not in ascending order.
If A =5, the list becomes 3/5, 5/5, 75% which clearly is 0.6, 1, 0.75 which is also not in ascending order.
For any value of A greater than 5, the second term A/5 is greater than 1 thus being less than the third term 0.75.
Therefore there is no whole number A that makes the list true.
The term to term rule is multiplying by 4 and if we continue doing this, we will move towards very large positive numbers.
This sequence, therefore, diverges to infinity
