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cupoosta [38]
3 years ago
8

Dahlia is simplifying (3 t) Superscript 4 using these steps:

Mathematics
1 answer:
DENIUS [597]3 years ago
5 0

Answer:

D would be the answer

Step-by-step explanation:

Took the test got it correct <33 good luck

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I’m not sure how to do this please help
Nikolay [14]

Answer:

B :step 2   she didnt collect all the like terms and calculate

Step-by-step explanation:

first rewrite  remove all (  )Parentheses

2nd   collect all like terms and calculate

a^4 + 7a -16 -12^a^3 + 5a -3

a^4 + 12a - 19 - 12a^3     ( Like terms are 7a +5a  and -16 +-3)

so she skipped the second step

3 0
2 years ago
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
3 years ago
Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!​
Misha Larkins [42]

Answer:

[0.25, 2]

Step-by-step explanation:

We have

4t² ≤ 9t-2

subtract 9t-2 from both sides to make this a quadratic

4t²-9t+2 ≤ 0

To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.

4t²-9t+2=0

We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as

4t²-8t-t+2=0

4t(t-2)-1(t-2)=0

(4t-1)(t-2)=0

Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of

4t²-9t+2 ≤ 0

For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct

For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct

For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.

Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]

8 0
3 years ago
HELP ASAP PLEASE!!!!!!!!
WARRIOR [948]

Answer:

ĉu vi scias ion, ni supozeble ne scias tion, jes

7 0
3 years ago
Simplify e with an exponent of in6
blagie [28]

Answer:

Step-by-step explanation:

I think the exponent is ln6, not in6.

e^(ln 6)= 6

3 0
3 years ago
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