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dsp73
3 years ago
9

80 members decreased by 65% =

Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0

65% of 80 is 52

52 Members

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7/10 times y minus 3/10 when y equals 1/7
Oduvanchick [21]

Answer:

Exact form : - 1/5

Decimal form : -0.2

Step-by-step explanation: Substitute the value of the variable into the equation and then simplify.

Hope this helps you out. If not, comment and let me know. Good luck, mate! ☺

-Leif the Insane Puppy Loving Weirdo-

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I don't know this can someone help me?
Gemiola [76]

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F(x)=49 range and domain
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3 years ago
Element X decays radioactively with a half life of 13 minutes. If there are 530 grams of Element X, how long, to the nearest ten
Leona [35]

Answer:

t \approx 50.4\,min

Step-by-step explanation:

The time constant of the element X is:

\tau = \frac{13\,min}{\ln 2}

\tau = 18.755\,min

The decay function has the following form:

\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }

t = -\tau \cdot \ln \frac{m}{m_{o}}

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6 0
3 years ago
The amount of water in a bottle is approximately normally distributed with a mean of 2.55 liters with a standard deviation of 0.
Natalka [10]

Answer:

a) P(X

b) P(\bar X

c) P(\bar X

d) For part a we are just finding the probability that an individual bottle would have a value of 2.52 liters or less. So we can't compare the result of part a with the results for parts b and c.

If we see part b and c are similar but the difference it's on the sample size for part b we just have a sample size 4 and for part c we have a sample size of 25. The differences are because we have a higher standard error for part b compared to part c.

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z

Let X the random variable that represent the amount of water in a bottle of a population, and for this case we know the distribution for X is given by:

X \sim N(2.55,0.035)

a. What is the probability that an individual bottle contains less than 2.52 liters?

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(X

b. If a sample of 4 bottles is selected, what is the probability that the sample mean amount contained is less than 2.52 liters? (Round to three decimal places as noeded)

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(2.55,\frac{0.035}{\sqrt{4}})

The z score on this case is given by this formula:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we replace the values that we have we got:

z=\frac{2.52-2.55}{\frac{0.035}{\sqrt{4}}}=-1.714

For this case we can use a table or excel to find the probability required:

P(\bar X

c. If a sample of 25 bottles is selected, what is the probability that the sample mean amount contained is less than 2.52 liters? (Round to three decimal places as needed.)

The z score on this case is given by this formula:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we replace the values that we have we got:

z=\frac{2.52-2.55}{\frac{0.035}{\sqrt{25}}}=-4.286

For this case we can use a table or excel to find the probability required:

P(\bar X

d. Explain the difference in the results of (a) and (c)

For part a we are just finding the probability that an individual bottle would have a value of 2.52 liters or less. So we can't compare the result of part a with the results for parts b and c.

If we see part b and c are similar but the difference it's on the sample size for part b we just have a sample size 4 and for part c we have a sample size of 25. The differences are because we have a higher standard error for part b compared to part c.  

3 0
3 years ago
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