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pashok25 [27]
3 years ago
12

Rosa had 592 stickers. She gave 212 stickers to Meg.

Mathematics
1 answer:
Ratling [72]3 years ago
4 0

Answer: I need help with this as fast as someone can. PLS let me know who to do it

Step-by-step explanation:

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On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
3 years ago
Read 2 more answers
ive males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five
Nonamiya [84]

Answer:

a   c    d  

.............................................

5 0
3 years ago
The 100th term of 70​, 110​, 150​, ... is .
Paul [167]
You are adding 40 every time.
The 100th term is 7+(99*40)=3967
5 0
3 years ago
Read 2 more answers
(4.161 x 10^2) + (4.56 x 10^3)
VladimirAG [237]
Convert to stand both expressions to standard form:
416.1 + 4,560

Add:
4,976.1
5 0
3 years ago
PLEASE HELP!! brainliest if correct!!
Sonja [21]
Graph #1: No
Graph #2: Yes
Graph #3: No
Graph #4: No
Graph #5: No
Graph #6: Yes

Reasoning:

The vertical line test is a test that determines wether a graph is a function or a relation. The vertical line test shows that if you construct a vertical line through any point on the graph, then the vertical line should only intercept the graph once for it to be a function.
6 0
2 years ago
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