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Umnica [9.8K]
3 years ago
6

If f(x) = x - 3 and g(x) = x^2, what is the value of (fºg)(2)? 1. 1 2. -1 3. 4 4. -4

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0

Answer:

1

Step-by-step explanation:

First we need to find g (2) from g (2) = 2 ^ 2 to 4.

the result is 4, so f (4) asks, so f (4) = 4-3 = 1

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Slope of line that passes through points (2,1) and (17,-17)
mojhsa [17]

Answer: y = -1,2x + 3.4

Step-by-step explanation:

y = ax + b

(2,1)      => 1    = 2a + b (1)

(17,-17) => -17 =17a + b (2)

Using caculator Mode => 5 =>1

We get : a=- 1.2 , b = 3.4

=> y = -1.2x + 3.4

7 0
3 years ago
PLEASE HELP ME ASAP!<br> Find are and perimeter!!!!
dangina [55]
Area =  the top semicircle + the rectangle AEBD

= 1/2 pi*6^2 + 6*12  =  128.55 cm^2 to nearest 100th

Perimeter = 6pi + 12 + 2 pi * 3 = 49.70 cm
6 0
3 years ago
HELP?
poizon [28]
My "work" is to enter the equations into a graphing calculator and let it show me the answers--just as your "work" is to copy the question to Brainly.

The solutions are
  (x, y) = (-0.5, 7.5)
  (x, y) = (3, 25)

_____
When you equate the expressions for y, you get the quadratic
  2x² -5x -3 = 0
  (2x +1)(x -3) = 0
  x = -1/2 or 3
  y = 5(x +2) = 15/2 or 25

4 0
3 years ago
Simplify<br> 29 – 4.37 +(-5.68)<br><br> Please help me how to simplify this PLEASE
viktelen [127]
Answer: 18.95

Hope this is correct :)
6 0
2 years ago
indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and
vladimir1956 [14]

The equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is <u>12x - 2y = 13</u>.

In the question, we are asked to indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5).

The slope of the line with endpoints (-1,6) and (5,5), can be calculated as:

m = (6 - 5)/(-1 - 5) = 1/(-6) = -1/6.

Thus, the slope of the perpendicular bisector = -1/m = -1/(-1/6) = 6.

The perpendicular bisector passes through the midpoint of the line with endpoints (-1,6) and (5,5), which can be calculated as:

(x₁, y₁) = ( {(-1 + 5)/2},{(6 + 5)/2} ),

or, (x₁,y₁) = (2, 11/2).

Thus, the required equation can be shown as:

(y - 11/2) = 6(x - 2), which can be shown in the standard form as follows:

(2y - 11)/2 = 6x - 12,

or, 2y - 11 = 12x - 24,

or, 12x - 2y = 13.

Thus, the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is <u>12x - 2y = 13</u>.

Learn more about the equation of perpendicular bisector at

brainly.com/question/20608689

#SPJ4

4 0
2 years ago
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