27 is what percent of 150 explain

Which pair of points have a slope of -3/5?

Allushta [10]

Answer:

No of these answers has a slope of $\frac{-3}{5}$ . My guess is B becasue its close to $\frac{-3}{5}$ unless the 5 is supposed to be negative

Step-by-step explanation:

You have to use the slope formula $\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

( $x_{1}$ , $y_{1}$ ), ( $x_{2}$ , $y_{2}$ )

(4, 0), (-2, 10) $\frac{10 - 0 }{-2 - 4 }= \frac{10}{6}$ you have to simplfy, the answer will be $\frac{5}{3}$

(10, -2), (0, 4) $\frac{4 - -2 }{0- 10 }= \frac{6}{-10}$ you have to simplfy, the answer will be $\frac{3}{-5}$

(4, 2), (10, 4) $\frac{4 - 2 }{10 - 4 }= \frac{2}{6}$ you have to simplfy, the answer will be $\frac{1}{3}$

(-4, -10),(0, -2) $\frac{{-2- -10} }{0 - -4 }= \frac{8}{4}$ you have to simplfy, the answer will be $\frac{2}{1} =2$

5 0

2 years ago

(4x + 17)<br> What is the measure of AC ?<br> Enter your answer in the box.<br> (4x – 3.5)

Natasha2012 [34]

Answer: $AC=41\°$

Step-by-step explanation:

<h3> The complete exercise is attached.</h3>

For this exercise it is important to remember that, by definition, if an angle formed by two intersecting chords has its vertex on a circle, this is called an "Inscribed angle".

The following formula is used to calculate the measure of an Inscribed angle:

$Inscribed\ angle = \frac{1}{2}\ Intercepted\ Arc$

You can identify in the figure that:

$Inscribed\ angle=ABC=(4x -3.5)\\\\Intercepted\ Arc=AC=(4x + 17)$

Then you can substitute values into the formula and solve for "x":

$(4x -3.5)= \frac{1}{2}(4x + 17)\\\\8x-7=4x+17\\\\4x=24\\\\x=6$

Then, AC is:

$AC=(4(6)+ 17)\\\\AC=24+17\\\\AC=41\°$

3 0

3 years ago

The height h in feet of a ball thrown vertically upward from the top of a 288-foot tall building is given by h=288+48t-16t^2 whe

mr Goodwill [35]

6 sec can take penny to strike the ground.

Solution:

Given data:

$H_0=288$ feet

$V_0=48$ feet

$h(t)=288+48t-16t^2$

Re-arrange the terms from greatest degree to smallest degree.

$h(t)=-16t^2+48t+288$

We can solve it by applying quadratic formula,

$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a = –16, b = 48, c = 288

$$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}$

$$t=\frac{-48\pm \sqrt{2304+18432}}{-32}$

$$t=\frac{-48\pm \sqrt{20736}}{-32}$

$$t=\frac{-48\pm144}{-32}$

Now, write find two t's using plus and minus operation.

$$t=\frac{-48+144}{-32},\ \ t=\frac{-48-144}{-32}$

$$t=\frac{96}{-32},\ \ t=\frac{-192}{-32}$

t = –3 (or) t = 6

We cannot write time is negative. so neglect t = –3.

Therefore t = 6.

Hence 6 sec can take penny to strike the ground.

8 0

2 years ago

Graph the line that passes through the points (9,-8) and (9,6) and determine the

avanturin [10]

Answer:

Step-by-step explanation:

The standard form of equation of a line is expressed as y = mx+c

m is the slope

c is the y intercept

Note that the line does not have a slope and the x intercept of the line is a point where the line cuts the x axis. Hence the equation of the line will be expressed as x = c where c is the x intercept;

<em>From the graph, the x intercept =9. Hence the equation of the given line is x = 9</em>

7 0

2 years ago

Write an equation of the line passing through the point (3, -1) and parallel to the line y=2/3x - 5. Show work

alex41 [277]

Answer:

The answer is: y = 2/3x - 3

Step-by-step explanation:

Given point: (3, -1)

Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.

Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:

y - y1 = m(x - x1)

y - (-1) = 2/3(x - 3)

y + 1 = 2/3x - 6/3

y + 1 = 2/3x - 2

y = 2/3x - 3

Proof:

f(3) = 2/3(3) - 3

= 6/3 - 3

= 2 - 3

= -1, giving the point (3, -1)

Hope this helps! Have an Awesome Day!! :-)

6 0

2 years ago