Answer:
3 2/3 is greater
Step-by-step explanation:
3 2/3 is 3.6666 while √11 is 3.32
20.sometimes
21.always
22.always
23.sometimes
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:
<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.
<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.
If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.
The formula to calculate the z-score of a certain value is:
z = (x - (mean))/(standard deviation)
In this example, the x-value is 450, the S.D. is 100, and the mean is 500.
So, substitute these values into the formula.
z = (450-(500))/100
z=-50/100
z=-0.5
Therefore, the z-score is -0.5.
Answer:
10 1/12
Step-by-step explanation:
In order to subtract fractions, you have to give them a common denominator.
18 1/2 can be rewritten as 18 6/12, as they are the same thing and 6/12 simplifies to 1/2. We make it 6/12 because we have to subtract it by 8 5/12, and the denominators are both 12.
So now we have 18 6/12 - 8 5/12, which gives us 10 1/12.
